Answer:
The Proof is below.
Step-by-step explanation:
Given:

To Prove:

Proof:
In ΔLPM and ΔNPM
……….{Given}
……….{Given}
……….{Reflexive Property}
ΔLPM ≅ ΔNPM ….{ By Side-Side-Side congruence test}
∴ ∠LMP ≅ ∠NMP ...{Corresponding parts of congruent triangles (c.p.c.t).}.....( 1 )
Now In ΔLMQ and ΔNMQ
……….{Given}
∠LMQ ≅ ∠NMQ ..........{From 1 above}
……….{Reflexive Property}
ΔLMQ ≅ ΔNMQ ....{ By Side-Angle-Side Congruence test}
∴
...{Corresponding parts of congruent triangles (c.p.c.t).}.....Proved
Answer:
It got cut off, but the approximate y intercept is 3 and slope intercept form is
y = x + 3 and I used the points 0,3 and 3,6 to calculate the slope using the slope equation y1 - y2/x1 - x2
Hope this helped and brainliest please!
9514 1404 393
Answer:
a) V = 4w²h
b) SA = 4w² +10wh
c) SA = 4w² +37.5/w
d) C = 40w² +225/w
Step-by-step explanation:
The relevant formulas are ...
V = LWH
base area = LW
lateral area = H(2(L+W))
__
a) The length is 4 times the width, so the volume is ...
V = (4w)(w)(h)
V = 4w²h
__
b) The total surface area is the sum of the base area and the lateral area:
SA = base area + lateral area
SA = (4w)(w) + 2h(4w +w)
SA = 4w² +10wh
__
c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...
15 = 4w²h
h = 15/(4w²)
Then the surface area is ...
SA = 4w² +10w(15/(4w²))
SA = 4w² +37.5/w
__
d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:
C = 10(4w²) +6(37.5/w)
C = 40w² +225/w
Answer is 0= -2
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