All categories

3 years ago

Hello Pleasa help ASAP !!!!

Mathematics

1 answer:

cricket20 [7]3 years ago

3 0

Would have to go with A.

Most of us have to invest in study time for recall at test time.

You might be interested in

HELP!!!!!!!!!!! !!!!!!!!!!

Sonja [21]

Answer:

second one is 3, the last one is 4560

Step-by-step explanation:

5 0

2 years ago

What is 2,901 rounded to the nearest hundred

beks73 [17]

Answer:

2,900

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Evaluate csc(-315°).

Maru [420]

Answer:

$\frac{2}{\sqrt{2} } = \sqrt{2}$

Step-by-step explanation:

Notice from the attached image that -315 degrees is the same as 45 degrees.

Recall as well that the csc function is defined as the reciprocal of the sine function: $csc(x)=\frac{1}{sin(x)}$

Then, you need to evaluate $\frac{1}{sin(45)} = 1/\frac{\sqrt{2} }{2} = \frac{2}{\sqrt{2} } =\sqrt{2}$

8 0

2 years ago

A line with a slope of -3/4 that passes through the point (-14,4).

damaskus [11]

Answer:

y=-3/4x-13/2

Step-by-step explanation:

This should be the answer, I am not 100% though

I did y-4=-3/4x(x+14)

6 0

2 years ago

Read 2 more answers

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

3 years ago