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mylen [45]
3 years ago
12

I need the equation and the answer and how to do it, thank you<3

Mathematics
1 answer:
vazorg [7]3 years ago
3 0

Answer:

19=5+(j times 2/3) j=21

Step-by-step explanation:

While reading out the equation, you understand that Hannah's 19 Jolly Ranchers is what the equation is being set to. 5 more means +5. 2/3 of J can be written as (2/3 times J). You can solve for J by setting the equation to J.

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∠3 and ∠4 are angles that must be supplementary.
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3 years ago
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Put the following fractions in order of size starting with the one with the least value 5/16 1/2 3/4 5/8 1/4
Stolb23 [73]

Answer:

1/4, 5/16, 1/2, 5/8, 3/4

Step-by-step explanation:

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2 years ago
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Kelly collected $15, $15, $25, and $29 in the last 4 donations for the class fundraiser. The mean of the donations is _____?
photoshop1234 [79]

Answer:

21

Step-by-step explanation:

To find the mean, add up all the numbers

15+15+25+29 =84

Divide by the number of numbers

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2 years ago
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An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
a data set has a mean of 68 and standard deviation of 6. An element in this set is 51. What is z-score for 51? Round your answer
gogolik [260]

z = -2.83

<u>Explanation:</u>

Given:

Mean, μ = 68

Standard deviation, σ = 6

Data point, x = 51

Z score, z = ?

We know:

z = \frac{data point - mean}{standard deviation} \\\\z = \frac{x - u}{p}

Substituting the value we get:

z = \frac{51-68}{6} \\\\z = -2.83

A negative z score says that the data point is below average.

4 0
3 years ago
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