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2 years ago

PLEASE ANSWER DONT IGNORE ): I WILL GIVE U BRAINLIEST AND THANKS AND 5 STARS

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

7 0

Answer:

Niether of them are correct

Step-by-step explanation:

If you actually put into your calculator 2^28, it equals 268,435,456. This is because you're not just squaring 28, you are multiplying 2 by 2-- 38 times. This will quickly add up, even if you start out with 2 it will create a very large number.

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A leather vest multiplied vero 0.63 by 1.8 point what is the correct product

labwork [276]

The answers of the product is 1.8 * 0.63 = 1.134

4 0

2 years ago

32% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

Tems11 [23]

Answer:

a) $P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

b) $P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

c) $P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.32)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

Part b

$P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]$

$P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211$

$P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

Part c

$P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264$

$P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218$

$P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123$

$P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

6 0

3 years ago

Help me on this please I’d appreciate it

guajiro [1.7K]

Step-by-step explanation:

your friend is closer to the school (b)

it's graph covers less area..

4 0

2 years ago

PLEASE HELP! I have a deadline tonight ,I have to get this done! thank you!!<br> Two questions (:

Viktor [21]

Both of your answers are correct. In the first equation, if you were to substitute 3 for x, because you have to do exponents first, you have 3^2, which is 9, and 9*6 =54. If you were to substitute -3 for x again you would have to do the exponents first which would be -3^2 which is 9, and 9*6 = 54.

For the second question, if I substitute 0.75 for t, I get -9 + 18 + 7. This is equal to 16, and therefore the answer would be D. Hope this helps! :D. Let me know if you have questions about my explanation, and feel free to post more questions.

3 0

2 years ago

The probabilty of getting an A in math is 0.65 and the probability of getting an a in science is 0.62 whats the probability of g

ruslelena [56]

Answer:

The probability of getting an a in both courses is 1.27

Step-by-step explanation:

Probability of getting A in Math, P(M) = 0.6 5

Probability of getting A in Science, P(S) = 0.62

Required probability of getting A in both courses, P(M and S)

= P(M) + P(S)

= 0.65 + 0.62

= 1.27

6 0

2 years ago