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2 years ago

Which is an equation of the line that passes through (2,-5) and (6, 3)?

Mathematics

1 answer:

Stolb23 [73]2 years ago

8 0

Answer:

Step-by-step explanation:

Your answer is D trust me

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-4 -11 = ?

kodGreya [7K]

Answer:

A) -15, 5, 2

Step-by-step explanation:

8 0

2 years ago

What is the domain of this

Kaylis [27]

Answer:

$\boxed{\sf B. \ All \ real \ numbers}$

Step-by-step explanation:

The domain is all possible values for x.

$f(x)=(\frac{1}{4} )^x$

There are no restrictions on x.

The domain is all real numbers.

3 0

2 years ago

Read 2 more answers

illey wants to solve the following equations using the method of elimination: y = x – 2 y = 4x – 8 What number should y = x – 2

lbvjy [14]

The second equation has 4x in it t. So to eliminate X, you need to multiply y = x-2 by -4, so the x would become -4x.

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Chuge%5Cmathfrak%5Cpurple%7Bplease%20%5C%3A%20solve..%7D%20%5C%5C%20%20%5C%5C%20%5Chuge%5Cma

Verdich [7]

Answer:

2²4

4²=16

4+16=20

hope it helps :)

8 0

2 years ago

What are the zeros of the quadratic function?<br> y = x^2 - 2x - 15

Pie

Answer:

$x=\frac{1+\sqrt{31}}{2},\:x=\frac{1-\sqrt{31}}{2}$

Step-by-step explanation:

$-> 0=2x^2-2x-15$

-zeros means the solution aka x intercept, meaning y=0

$x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:2\left(-15\right)}}{2\cdot \:2}$

=> according to quadratic formula

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

where $ax^2+bx+c=0$

=> $x_{1,\:2}=\frac{-\left(-2\right)\pm \:2\sqrt{31}}{2\cdot \:2}$

simplify

$x_1=\frac{-\left(-2\right)+2\sqrt{31}}{2\cdot \:2},\:x_2=\frac{-\left(-2\right)-2\sqrt{31}}{2\cdot \:2}$

$x=\frac{1+\sqrt{31}}{2},\:x=\frac{1-\sqrt{31}}{2}$

Cannot simplify farther

3 0

2 years ago