Write an equation in point-slope form that describes the line with a slope of -3 that contains the point (1,2)
1 answer:
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<u>Given</u>:
The given function is
We need to determine the value of the discriminant f and also to determine the distinct real number zeros of f.
<u>Discriminant</u>:
The discriminant can be determined using the formula,
Now, we shall determine the discriminant of the function
Substituting the values in the formula, we have;
Thus, the value of the discriminant of f is -92.
<u>Distinct roots:</u>
The distinct zeros of the function f can be determined by
(1) If , then the function has 2 real roots.
(2) If , then the function has 2 real roots ( or one repeated root).
(3) If , then the function has 2 imaginary roots (or no real roots).
Since, the discriminant is , then the function has no real roots or 2 imaginary roots.
Thus, the function has 2 imaginary roots.
Answer:
A) The vertex ( h , k) = ( -2 , -18)
B) The minimum value of the given function = - 18
C) The Axis of the symmetry for f(t) is y -axis
Step-by-step explanation:
A)
Given a parabola f(t) = t² + 4 t − 14
f(t) = t² + 2(2) t + (2)²-4− 14
f(t) = (t +2)² - 18
Let comparing y = (x +2)² -18
(x +2)² = y + 18
(x-h))² = 4 a ( y - k))²
<em>The vertex ( h , k) = ( -2 , -18)</em>
B)
Given a parabola f(t) = t² + 4 t − 14
Differentiating with respective to 't'
f¹(t) = 2 t + 4
f¹(t) = 2 t + 4 = 0
now
Again Differentiating with respective to 't'
f(x) has a minimum value at t = -2
Given f(t) = t² + 4 t − 14
f( -2) = 4 + 4(-2) -14 = 4 -8 -14 = -18
The minimum value of the given function = - 18
C)
f(t) = (t +2)² - 18
Let comparing y = (x +2)² -18
(x +2)² = y + 18
(x-h))² = 4 a ( y - k))²
The vertex ( h , k) = ( -2 , -18)
The Axis of the symmetry for f(t) is y -axis