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zalisa [80]
1 year ago
14

Find the Z score to the nearest hundred thousand satisfies the given condition 0.166 square units of the standard normal distrib

ution is to the left of the Z
Mathematics
1 answer:
sergij07 [2.7K]1 year ago
8 0

The sum of the total area of a distribution is equal to 1. In our problem, we have 0.166 square units to the left of our value, therefore, we have the following area on the right

1-0.166=0.834

Using a z-table, we can find the corresponding z-value for this area to the right

The corresponding z-score to this area is 0.97, however, this value is below the mean, therefore it is negative.

The coresponding z-value is

z=-0.97

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A triangle has a perimeter of 18 inches. If one side has length 8 inches, find the length of the shortest side if the other leng
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8 0
3 years ago
A taxi driver wrote a formula to represent the mileage and fee for his last customer. He wrote the equation 3.00 + 0.50m =9.50,
Lemur [1.5K]
3.00 + 0.50m = 9.50

2. true 
5. true


4 0
3 years ago
Read 2 more answers
You row a canoe x miles per hour down a river for 20 minutes. On the return trip, you travel 1 mile per hour slower. The return
ozzi

Answer:

Total Distance = 2 miles

Step-by-step explanation:

We know D = RT where

D is distance

R is rate (speed)

T is time

First Leg:

Rate = x mph

Time = 20/60 = 1/3 hour

Hence, D = RT, Distance = x * 1/3 = x/3 miles

Second Leg:

Rate = x - 1

Time = 30/60 = 1/2 hour

Distance = (x - 1) * 1/2 = (x-1)/2

Total distance is the sum of both the legs, hence,

Total distance = \frac{x}{3}+\frac{x-1}{2}=\frac{2x+3(x-1)}{6}=\frac{2x+3x-3}{6}=\frac{5x-3}{6} miles

Since both the distance are equal we can equate and solve:

\frac{x}{3}=\frac{x-1}{2}\\2x=3x-3\\x=3

Plugging this x = 3 into the total distance expression, we get:

\frac{5x-3}{6}\\\frac{5(3)-3}{6}\\=2

Total distance, 2 miles

5 0
3 years ago
a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be
ElenaW [278]

\sf\huge\underline{\star Solution:-}

\rightarrowLet the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

\rightarrowNow, clearly it is forming a triangle.

So, in triangle ABC,

\rightarrow\sf{Tan50° \:= \: \frac{BC}{AC}}

\rightarrow\sf{1.19 \:= \: \frac{BC}{50}}

\rightarrow\sf{1.19 ×50\:= \: BC}

\rightarrow\sf{59.5m\:= \: BC}

\rightarrowHence, BC = 59.5m

So, BD(total height of the tower)\sf{ = \:BC+CD}

\sf{= \:59.5+1.65}

\sf{=\: 61.15m}

Therefore, total height of the tower =\sf\purple{ 61.15m.}

________________________________

Hope it helps you:)

5 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!!
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I'm not sure what the question is but it looks like it's B
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3 years ago
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