The point that passes through the line Y-5=-3(x-4) is (-4,7). You are very welcome.
All of them or which one???
It is: i √6 i believe :))
Answer:
B. 0
Step-by-step explanation:
Given
g(t) = t² - t
f(x) = 1 + x
Required
Find g(f(3) - 2f(1))
First, we'll solve for f(3)
Given that f(x) = 1 + x
f(3) = 1 + 3
f(3) = 4
Then, we'll solve for 2f(1)
2f(1) = 2 * f(1)
2f(1) = 2 * (1 + 1)
2f(1) = 2 * 2
2f(1) = 4
Substitute the values of f(3) and 2f(1) in g(f(3) - 2f(1))
g(f(3) - 2f(1)) = g(4 - 4)
g(f(3) - 2f(1)) = g(0)
Now, we'll solve for g(0)
Given that g(t) = t² - t
g(0) = 0² - 0
g(0) = 0 - 0
g(0) = 0
Hence, g(f(3) - 2f(1)) = 0
From the list of given options, the correct answer is B. 0
you might have to google search because i can barley see the table
