The given data is Magnification, M = 15
Length of the tube , L = 16 cm
The focal length of the lens can be calculated by:
M = L/F
Substituting the value, we get:
15 = 16/f
f = 16/15
f = 1.067 cm
Using the equation of magnification we get,
M = v/u
Substituting the values we get:
15 = v/u
v = 15 u
With the help of lens formula, calculate the object distance:
1/f = 1/v + 1/u
Substituting the value we get,
1/1.067 = 1/15u + 1/u
0.937 = 1.067/u
u = 1.13 cm or 1.1 cm.
Hence, the object distance is 1.1 cm.
Answer:
The correct answer is option - C. low power objective.
Explanation:
In microscopes, low power objectives have a wide field of view and use to study the many smaller specimens or large specimens. 10X is the power of the low objective.
To study the depth of the field the lower objective rotated and aligned on the place over the specimen. When you move to high power objective the field of view gets close in and only can study the smaller specimen or small section of a large specimen.
Thus, the correct answer is option - C. low power objectives.
I believe that the answer is b
Answer:
A.Both store materials needed by the organism
hope it helps..
Nitrogen is released to the abiotic parts of the biosphere from the process death and by bacteria.
