Answer:
1. The final temperature of the metal is 111 °C.
2. The change in the temperature of the water is 6.2 °C
3. The change in the temperature of the metal is 40.6 °C.
Explanation:
From the question given above, the following data were obtained:
Initial temperature of metal (Tₘ₁) = 70.4 °C
Initial temperature of water (Tᵥᵥ₁) = 23.6 °C
Equilibrium temperature (Tₑ) = 29.8 °C
1. Determination of the final temperature of metal.
We'll begin by calculating the change in temperature of the metal. This can be obtained as follow:
Initial temperature of metal (Tₘ₁) = 70.4 °C
Equilibrium temperature (Tₑ) = 29.8 °C
Change in temperature of metal (ΔTₘ) =?
ΔTₘ = Tₘ₁ – Tₑ
ΔTₘ = 70.4 – 29.8
ΔTₘ = 40.6 °C
Finally, we shall determine the final temperature of the metal. This can be obtained as follow:
Initial temperature of metal (Tₘ₁) = 70.4 °C
Change in temperature of water (ΔTₘ) = 40.6 °C
Final temperature of metal (Tₘ₂) =?
40.6 = Tₘ₂ – 70.4
Collect like terms
40.6 + 70.4 = Tₘ₂
111 = Tₘ₂
Tₘ₂ = 111 °C
Thus, the final temperature of the metal is 111 °C
2. Determination of the change in the temperature of the water.
Initial temperature of water (Tᵥᵥ₁) = 23.6 °C
Equilibrium temperature (Tₑ) = 29.8 °C
Change in temperature of water (ΔTᵥᵥ) =?
ΔTᵥᵥ = Tₑ – Tᵥᵥ₁
ΔTᵥᵥ = 29.8 – 23.6
ΔTᵥᵥ = 6.2 °C
Therefore, the change in the temperature of the water is 6.2 °C
3. Determination of the change in the temperature of the metal.
The change in the temperature of the metal is 40.6 °C.
Please solution 1 above for explanation.
