Yes because they atom with a stable octet electrons is less reactive it does not need any more electrons while an atom that has an partially filled electrons need more electrons to complete octet structure
B) just learn that you move the decimal right as numbers go higher and left if numbers decrease
So 1.75 km =1750000
Move decimal to the left to get a scientific notation
So 1.75 x 10^6
Brainliest?
Answer:

Explanation:
Hello,
In this case, for the given reaction, the equilibrium constant turns out:
![Keq=\frac{[B]}{[A]}=\frac{0.5M}{1.5M} =1/3](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BB%5D%7D%7B%5BA%5D%7D%3D%5Cfrac%7B0.5M%7D%7B1.5M%7D%20%3D1%2F3)
Nonetheless, we are asked for the reverse equilibrium constant that is:

Which is greater than one.
In such a way, the Gibbs free energy turns out:

Now, since the reverse equilibrium constant is greater than zero its natural logarithm is positive, therefore with the initial minus, the Gibbs free energy is less than zero, that is, negative.
Answer:
356.484 g.
Explanation:
- Molarity (M) is defined as the no. of moles of solute (NaCl) dissolved in a 1.0 L of the solvent.
<em>M = (no. of moles of NaCl)/(volume of the solution (L))</em>
M = 6.10 M, volume of the solution = 1.0 L.
∴ No. of moles of NaCl = (M)(volume of the solution (L)) = (6.10 M)(1.0 L) = 6.10 mol.
<em>∵ no. of moles of NaCl = (mass of NaCl)/(molar mass of NaCl)</em>
∴ Mass of NaCl = (no. of moles of NaCl)(molar mass of NaCl) = (6.10 mol)(58.44 g/mol) = 356.484 g.
Answer: 128 g/mol
Explanation:
Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.
Mathematically, that is:

Since, you know the ratio of two rates and the molar mass of one gas, you can calculate the molar mass of the other gas.
The molar mass of the oxygen molecule, O₂ = 2×16.0g/mol = 32.0 g/mol.
In the coming equations, I will use 32 g/mol for simplicity of writing.

So, the molecular mass of the unnknown gas is 128 g/mol.