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Leni [432]
3 years ago
14

Phase change is based on the_________, which states that phase change occurs with changing average kinetic energy. a. Law of con

servation of Mass b. Law of definite proportions c. Kinetic Molecular Theory d. law of multiple proportions
Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

d but I'm not sure.............

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On a roller coaster, where is maximum kinetic energy I’ll mark the brainiest.
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its the pink one I think

Explanation:

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How many grarns would 3 moles of carbon dioxide (CO2) weigh? (round to the
BigorU [14]

Mass of CO₂ = 132 g

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mole also can be formulated :

\tt n=\dfrac{mass}{MW}

moles of CO₂ = 3

mass of CO₂(MW=44.01 g/mol) :

\tt mass=mol\times MW\\\\mass=3\times 44.01\\\\mass=132.03~g\approx 132~g

6 0
3 years ago
Helppppppppppp it’s due today pls help and thanks
Sergeu [11.5K]

Step 1: Evaporation

Step 1: condensation

Step 3: Sublimation

Step 4: Precipitation

Step 5: Transpiration

Step 6: Runoff

Step 7: Infiltration

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2 years ago
THIS IS DUE TODAY IF YOU HELP I WILL GIVE BRAINLIEST
sp2606 [1]

Answer:19. He says that he’s been really tired since several weeks ago. 20. A friend of us is going to pick us up at the airport. 21. I’ve worked like a waiter in the past, but I wouldn’t want to do it again. 22

Explanation:

7 0
3 years ago
How many moles of oxygen are needed to react with 87 grams of aluminum
labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

                              Al         :         O₂

                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

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3 years ago
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