1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VMariaS [17]
3 years ago
13

Can someone help me on B and C

Mathematics
1 answer:
Elis [28]3 years ago
6 0
B. If you look at the graph and go over 5cm and up 3m, you can see that that point is not near the others, so it can't be accurate according to the data on your graph. C. If you go over 3.2 cm on your graph, go up to where the other points are, and you will see that the most likely height would be about 4.7m. Try to imagine a line going through your graph around where the points are, that might help you see where other points would be. I hope that makes sense let me know if you need anything else I'm always happy to help :)
You might be interested in
Select the correct answer.
Pie

Answer:

a.

Step-by-step explanation:

a= y-k/ (x-h)^2

<h2>Make me a brain list</h2>
6 0
2 years ago
Find the area of the regular polygon​
Y_Kistochka [10]

Answer:

A = 374.123 ft^2

Step-by-step explanation:

First, lets calculate the perimeter:

Perimeter (p) = side length (s) * number of sides (n)

p = s * n

p = 12 * 6

p = 72

Next, lets find the apothem, which is the shortest length from any side to the middle. It's like the radius in a circle, but more complicated.

Apothem (a) = side length (s) / ( 2 * tan(180/number of sides (n)) )

a = \frac{s}{2 * tan (\frac{180}{n} )}

a = \frac{12}{2 * tan (\frac{180}{6} )}

a = \frac{12}{2 * \frac{\sqrt{3} }{3}}

a = \frac{12}{\frac{2\sqrt{3} }{3}}

a = \frac{12*3}{2\sqrt{3}}

a = \frac{6*3}{\sqrt{3}}

a = \frac{18}{\sqrt{3}}

Now, finally, to find the area of a regular polygon, we use the following equation:

Area (A) = ( apothem (a) * perimeter (p) ) / 2

A = \frac{a * p}{2}

A = \frac{\frac{18}{\sqrt{3} }  * 72}{2}

A = \frac{18}{\sqrt{3}}  * 36

A = \frac{640}{\sqrt{3}}

Turning into a decimal:

A = 374.123 ft ^2

8 0
2 years ago
Please help! Im begging!​
bekas [8.4K]

Alright, so we know that there are 7 days a week with 24 hours per day.

24x7= 168 hours a week.

Convert the problem to an equation using the percentage formula: P% * X = Y.

Let's take the 40% that is Sleep and use it in the percentage formula with the 168 hours.

40%x168= roughly 67 hours.

Hope this helped!

7 0
3 years ago
The length, l, that a spring is stretched varies directly as the amount of force, F, applied to the end of the spring. When a fo
Elina [12.6K]

Answer:

C. 4.5 inches

Step-by-step explanation:

Given the following data;

Force, F = 10 pounds

Extension, e = 3 inches

First of all, we would determine the spring constant (k) using the following formula;

Force = spring constant * extension

10 = spring constant * 3

Spring constant = 10/3

Spring constant = 3.33 pounds per inches.

Next, we would find the extension of the spring when a force of 15 pounds is applied;

F = ke

15 = 3.33 * e

Extension, e = 15/3.33

Extension, e = 4.5 inches.

7 0
3 years ago
Pls help me!!!!!!!!​
Tcecarenko [31]

Answer: 127,500

Step-by-step explanation: I just used a calculator

7 0
3 years ago
Read 2 more answers
Other questions:
  • (2.03)
    13·2 answers
  • Given k║p.
    9·1 answer
  • What is the equation of a line that passes through the point?
    6·1 answer
  • Question three..................
    5·1 answer
  • Which of the following is equivalent to (7x + 3y)(8x + 5y)?
    8·1 answer
  • Find the inverse of the matrix <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%266%5C%5C8%26-12%5C%5C%
    6·1 answer
  • HELP <br> what are the coefficients of 7x^4-9x^3+2x^2
    11·1 answer
  • What is the area of the parallelogram? 80 cm 2 40 cm 2 29 cm 58 cm 2
    10·2 answers
  • Solve the equation I will give brainly ​
    14·2 answers
  • If
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!