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Ne4ueva [31]
3 years ago
12

HILLCL

Mathematics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

Step-by-step explanation:

0.5*0.5*0.5*0.5 = 0.0625

(probability of tail) *(probability of tail) *(probability of head) *(probability of head)

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I need to know what the answer is we have to combine like terms 10-4+6(4-2)
Paladinen [302]

Answer:

18

Step-by-step explanation:

Solve the separate part of the equation first

6(4) 6(-2) would equal 24-12

Add it back in to get: 10 - 4 + 24 - 12

-4-12 and 10+24 are the like terms so

10+24 = 34 and -4-12 = -16

Equation in the end: 34-16

Simplify that to: 34-16 = 18

5 0
2 years ago
Read 2 more answers
Express the product 2x²+6x-8+x+3 in standard form.
xxTIMURxx [149]
2x²+6x-8+x+3 in standard form is 2x²+7x-5.

Hope this Helps!
7 0
3 years ago
Can someone give me a hand?<br><img src="https://tex.z-dn.net/?f=%7B5%7D%5E%7B2x%20%2B%203%7D%20%20-%2084%20%3D%200" id="TexForm
weqwewe [10]

First, add 84 to both sides, to isolate the exponential function.

Then, take the logarithm of both sides:

(2x+3)*log 5 = log 84

Solving for 2x+3, we get log 84 - log 5, and so

2x = -3 + log 84 - log 5.  Dividing both sides by -3, we obtain the final answer:

      -3 + log 84 - log 5

x = -----------------------------

                    2

8 0
3 years ago
Does it pass the vertical line test. Pls help.. <br> Is this a function?
inessss [21]

Answer:

This is a function

Step-by-step explanation:

The vertical line test is a test where you take a straight vertical line and move it from right to left. If during the test, the line touches two points at the same time, it's not a function. In this case, it is a function since it passes the vertical line test.

3 0
2 years ago
Read 2 more answers
The approximate distance between K and L is units. The approximate distance between L and J is units. If you join all three poin
ss7ja [257]

Answer:

The answer is below

Step-by-step explanation:

The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:

AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

Point J is at (-3, 3), point K is at (4, 3) and point L is at (1, -1). Hence:

The distance between K and L = KL = \sqrt{(-1-3)^2+(1-4)^2} =5\ units

The distance between J and L = JL = \sqrt{(-1-3)^2+(1-(-3))^2} =4\sqrt{2} \ units

The distance between K and J = JK = \sqrt{(3-3)^2+(-3-4)^2} =7\ units

Therefore, the perimeter of triangle JKL is:

Perimeter = KL + JL + JK = 5 + 4√2 + 7 = 17.66 units

8 0
3 years ago
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