The formula is
YC x YD = AY x YB
fill in what we know:
18 x 6 = 9 x YB
108 = 9 x YB
YB = 108 / 9
YB = 12
Answer:
4 2/3 ÷ 3 1/3= 1 2/5
Step-by-step explanation:
First, you turn the mixed terms into an improper fraction like this
4 2/3 → 14/3 because when you multiply 4 times 3 equaling 12 then having 2 then adding that you get 14/3.
3 1/3 → 10/3 because when you multiply 3*3=9 then having 1 and adding that you get 10/3.
Then, you do KCF which stands for <u>Keep Change Flip</u> so for this you would do: 14/3 ÷ 10/3 → 14/3 × 3/10
14 × 3 = 42 and 3 × 10= 30
Now being 42/30 this is considered an improper fraction in which you have to transform it into a mixed number like this:
(For this you need to find the greatest common factor)
42/30 → 42 and 30 greatest common factor is 6 because they are divisible and factor of 6.
Now you divide both the denominator and the numerator y 6 like this:
42 ÷ 6= 7
30 ÷ 6= 5
Now we have 7/5, this is still an improper number so we see how many times 7 can go to 5 which is once. So we have 1 as whole number, now we put the reminder as the numenator of the mix fraction keeping 5 as being the denominator.
Overall, We have our answer 1 2/5
I hope this helps :D
Answer:
m(x)
Step-by-step explanation:
they would have to pass the horizontal line test and the vertical line test for both the origional and the inverse.
b(x) does not pass the horizontal line test in any of the y values over 3
d(x) does not pass the horizontal line test for y=-9
p(x) does not pass the horizontal line test for positive y values
and m(x) has only one corresponding x value for every y value
Answer:
2 and 14/15
Step-by-step explanation:
Answer:
i) P(X<33) = 0.9232
ii) P(X>26) = 0.001
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 30
Given that the standard deviation of the Population = 4
Let 'X' be the Normal distribution
<u>Step(ii):-</u>
i)
Given that the random variable X = 33
>0
P(X<33) = P( Z<1.5)
= 1- P(Z>1.5)
= 1 - ( 0.5 - A(1.5))
= 0.5 + 0.4232
P(X<33) = 0.9232
<u>Step(iii) :-</u>
Given that the random variable X = 26
>0
P(X>26) = P( Z>3.5)
= 0.5 - A(3.5)
= 0.5 - 0.4990
= 0.001
P(X>26) = 0.001
