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3 years ago

I need help plzz. Dilate this by 1/3

Mathematics

2 answers:

leva [86]3 years ago

8 0

For this shape there are four points. The plotted ordered pairs are:
M = (3, 9)
N = (6, 0)
O = (3, 6)
P = (-3, 0)

All you have to do is multiply the BOTH x- and y-values by 1/3 on EACH ordered pair. And if it’s easier, you can divide by 3 as well. It’s the same thing.

M = (3, 9) = (3*1/3, 9*1/3) = (1, 3)
N = (6, 0) = (6*1/3, 0*1/3) = (2, 0)
O = (3, 6) = (3*1/3, 6*1/3) = (1, 2)
P = (-3, 0) = (-3*1/3, 0*1/3) = (-1, 0)

(1, 3) , (2, 0) , (1, 2) , and (-1, 0) are your points.

astra-53 [7]3 years ago

3 0

He is right math is not really my strong suit

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Which equation can be used to solve for x in the following diagram?

Setler [38]

∑ Hey, petalssquad10 ⊃

Answer:

( 10 x + 10 ) = 110

Step-by-step explanation:

As you can see this following diagram shown a vertical angles which are angles that are opposite of each other when two lines cross. You can also see it kind of look like a "x". Vertical angles also means that they have the same angle measure. A example is if this angle is "110" then the other sides equal to "110''.

Hence, the equation we can be used to solve for x in the following diagram is:

( 10 x + 10 ) = 110

You can also refer to the image below:

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2 years ago

Step 1: –10 + 8x < 6x – 4

Aleks04 [339]

Answer:

3 > x

Step-by-step explanation:

–2(5 – 4x) < 6x – 4

Step 1: –10 + 8x < 6x – 4

Step 2: –10 < –2x – 4

Step 3: –6 < –2x

Step 4: divide each side by by -2, remembering to flip the inequality

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6 0

3 years ago

Read 2 more answers

Write the following sentence into an expression using x as your variable: Myrna and Tom collect stamps. Tom has four more than h

balandron [24]

Answer: f(x) = x/2 + 4.

where f(x) is the number of stamps that Tom has, and x is the number of stamps that Myrna has.

Step-by-step explanation:

The statement is:

"Tom has four more than half the stamps that Myrna has"

For how is written, we can model the number of stamps that Tom has as a function f(x).

f(x) represents the number of stamps that Tom has, and x is the number of stamps that Myrna has.

Then:

"four more than a number" is written as:

N + 4 (where N is the number)

"Half the stamps that Myrna has" is written as:

x/2.

Then the whole statement can be modeled as:

f(x) = x/2 + 4.

notice that we have x/2, and f(x) must be a whole number, so Myrna must have an even number of stamps (in that case x/2 will be integer)

8 0

3 years ago

Location is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, ar

yKpoI14uk [10]

Answer:

We conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

We are given that Location A was observed for 18 days and location B was observed for 13 days.

On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4.

Let $\mu_1$ = true mean number of sales at location A.

$\mu_2$ = true mean number of sales at location B

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2\geq0$ or $\mu_1 \geq \mu_2$ {means that the true mean number of sales at location A is greater than or equal to the true mean number of sales at location B}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2$ or $\mu_1< \mu_2$ {means that the true mean number of sales at location A is fewer than the true mean number of sales at location B}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n__1_-_n__2-2$

where, $\bar X_1$ = sample average of items sold at location A = 39

$\bar X_2$ = sample average of items sold at location B = 49

$s_1$ = sample standard deviation of items sold at location A = 8

$s_2$ = sample standard deviation of items sold at location B = 4

$n_1$ = sample of days location A was observed = 18

$n_2$ = sample of days location B was observed = 13

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(18-1)\times 8^{2}+(13-1)\times 4^{2} }{18+13-2} }$ = 6.64

So, test statistics = $\frac{(39-49)-(0)}{6.64 \times \sqrt{\frac{1}{18}+\frac{1}{13} } }$ ~ $t_2_9$

= -4.14

The value of t test statistics is -4.14.

Now, at 0.01 significance level the t table gives critical value of -2.462 at 29 degree of freedom for left-tailed test.

Since our test statistics is less than the critical values of t as -2.462 > -4.14, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

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3 years ago

There is a cube with sides of 10 cm long and a sphere with a radius of 10 cm. How

zmey [24]

Answer:

vol of cube = 10 x 10 x 10 = 1000

vol of sphere = 4/3πr³ = 4/3 x 3.14 x 1000 = 4186.666

4186.666 - 1000 = 3186.666

I'm pretty sure this isn't the ans but I think the top part is right

5 0

3 years ago