$0.59 x 8 = 4.72
4.72 + 5.87 = 10.59
Hope this helped, please mark brainliest :)
Answer:
6
Step-by-step explanation:
You must find the least common multiple of their schedules.
The numbers 3 and 2 are their own prime factors, so the least common multiple of 3 and 2 is 6.
Six weekends must pass until they can both have someone over on the same night.
The number line below shows that the first time their sleepovers coincide is Week 6.
Let's first write the equation given
x²+6x-13=0
They have told us to use "Completing the square" method.
So we need write x²+6x-13 as a whole square.
x²+6x-13=0
x²+(2*3*x)-9-4 = 0
x²+(2*3*x)-3²=4
Now we can write the LHS as:
(x - 3)²=2²
Hence,
x-3 can either be 2 or -2
Now,
x - 3=2
x=5
Or,
x - 3=-2
x=1
Therefore now we know that x can either be 1 or 5. So the correct answer is Option B.