Solve for x^2 +11 + 121/4 = 125/4 for x
1 answer:
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The cost of pen and pencils are related to the number that can be bought
with a given amount of money.
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Reasons:
The given parameters are;
If the number number of pens and pencils James buys = 3 pens and 2 pencils, the amount James will have left = $2
If the number of pens and pencils James buys = 2 pens and 3 pencils, the amount James will have left = $6
The amount of money Judith has = The amount of money with James
The number of pens and pencil James and Judith can buy = 6 pens and 6 pencils
The cost of one pen = a
The cost of one pencil = b
Required:
To find the ordered pair (a, b)
Solution:
Let <em>X</em> represent the initial amount of money James has, we get;
X - (3·a + 2·b) = 2...(1)
X - (2·a + 3·b) = 6...(2)
2·X = 6·a + 6·b...(3)
Therefore;
X = (6·a + 6·b) ÷ 2 = 3·a + 3·b
Which from equation (1) gives;
3·a + 3·b - (3·a + 2·b) = 2
3·a + 3·b - 3·a - 2·b = 2
3·b - 2·b = 2
b = 2
Subtracting equation (1) from equation (2) gives;
(X - (2·a + 3·b)) - (X - (3·a + 2·b)) = 6 - 2 = 4
-2·a - 3·b + 3·a + 2·b = 4
a - b = 4
a = 4 + b
∴ a = 4 + 2 = 6
a = 6
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Learn more about word problems and simultaneous equations here:
<span>To graph this we find the x- and y-intercepts. The x-intercept would be at 8 and the y-intercept would be at 6.
Explanation<span>:
The equation is 6x+8y=48. An x-intercept is the point where the data crosses the x-axis. All points on this line will have a y-coordinate of 0, so we replace y with 0 and solve:
6x+8(0)=48
6x=48.
Divide both sides by 6:
6x/6=48/6
x=8.
We go to 8 on the x-axis and plot the point.
A y-intercept is the point where the data crosses the y-axis. All points on this line will have an x-coordinate of 9, so we replace x with 0 and solve: 6(0)+8y=48
0+8y=48
8y=48.
Divide both sides by 8:
8y/8 = 48/8
y=6.
We go up to 6 on the y-axis and plot the point. We then draw a line through these two points.</span></span>
Explanation<span>:
The equation is 6x+8y=48. An x-intercept is the point where the data crosses the x-axis. All points on this line will have a y-coordinate of 0, so we replace y with 0 and solve:
6x+8(0)=48
6x=48.
Divide both sides by 6:
6x/6=48/6
x=8.
We go to 8 on the x-axis and plot the point.
A y-intercept is the point where the data crosses the y-axis. All points on this line will have an x-coordinate of 9, so we replace x with 0 and solve: 6(0)+8y=48
0+8y=48
8y=48.
Divide both sides by 8:
8y/8 = 48/8
y=6.
We go up to 6 on the y-axis and plot the point. We then draw a line through these two points.</span></span>
Answer:
Area of the shaded region = 1.92 cm²
Step-by-step explanation:
From the picture attached,
Area of the shaded region = Area of the sector OMN - Area of the triangle OMN
Area of sector OMN =
Here, θ = Central angle of the sector
r = radius of the sector
Area of sector OMN =
= 15.708 square cm
Area of ΔOMN = 2(ΔOPN)
Area of ΔOPN =
Area of ΔOMN = OP × PN
In ΔOPN,
sin(25°) =
PN = ONsin(25°)
= 6sin(25°)
= 2.536 cm²
cos(25°) =
OP = ONcos(25°)
OP = 6cos(25°)
OP = 5.438 cm
Area of ΔOMN = 2.536 × 5.438
= 13.791 cm²
Area of the shaded region = 15.708 - 13.791 = 1.917 cm²
≈ 1.92 cm²
