There is a theorem that says that this angle (formed by thre points on the circumference) is half such arc called EF.
We can deduct it as well.
1) Call O the center of the circle. The central angle (EOF) = arc EF = 151°
2) Draw a chord from F to D and other chord from D to E.
You have constructed two triangles, FOD and DOE.
3) Triangle FOD has two sides equals (because both are the radius of the circcle). Then, this is an isosceles triangle and it has two angles of the same measure. Call this measure a.
4) Triangle DOE is also isosceles, for the same reason explained in the poiint 3. Call the measure of its equal angles b.
5) The sum of the angles of the two triangles is 180° + 180 ° = 360°.
This is a + a + b + b + (360 - central angle) = 360°
=> 2a + 2b = central angle
=> 2(a+b) = cantral angle
=> (a+b) = central angle / 2 = 151° / 2 =71.5°
(a+b) is the angle that you are looking for.
Then the answer is 71.5°
Hello from MrBillDoesMath!
Answer:
2 - i
Discussion:
Evaluate F(x) = x^3 - 2 x^2 when x = i.
i^2 = -1 for i^3 = i ( i^2) = i (-1) = -i
So F(i) = (i)^3 - 2 (i)^2
= -i - 2(-1)
= -i + 2
= 2 - i
which is the last answer shown
Thank you,
MrB
Answer:
Step-by-step explanation:
It is given that triangle AOC intersects a circle with center O, side AO is 10 inches and the diameter of the circle is 12 inches, thus
OC is the radius of the circle and is equal to 
.
Now, From ΔAOC, using the Pythagoras theorem, we get
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Answer:
y= -8/11 x=-63/11
Step-by-step explanation:
Rewrite equation
Step: Solve6x+y=−10for y
Step: Substitute−6x−10 for y in 4x−3y=14
Step: Substitute −8
/11 for x in y=−6x−10
y= −62
/11 --- (Simplify both sides of the equation)
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y= -8/11
x=-63/11
