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2 years ago

If MN = x+4 and DE = 3x-2, find x. (More info in pic)

Mathematics

1 answer:

algol [13]2 years ago

6 0

Answer: D) 10

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Explanation:

I'm assuming points M and N are midpoints of segments FD and FE respectively. If that's the case, then segment DE is twice as long compared to segment MN. We consider MN to be a midsegment.

So,

DE = 2*(MN)

3x-2 = 2*(x+4)

3x-2 = 2x+8

3x-2x = 8+2

x = 10

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Step-by-step explanation:

if u times 24x4=96

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3 years ago

Describe the translation of the function from the parent function f(x) = x².

kkurt [141]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
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\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
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\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
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$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\

\end{array}\\$

$\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
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now, notice the template above... now let's see your function $\bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}$

so.. what do you think was the shift then?

8 0

3 years ago

HELP QUICK GIVING 50 POINTS!!!

avanturin [10]

Answer:

64/3 cc or 64/3 cm³

Step-by-step explanation:

The formula for the volume of a triangular pyramid is

V = (1/3)(area of base)(height)

Here we have a square prism (actually, a cube), whose square base is 4 cm by 4 cm (4 cm is the cube root of 64 cc). The height of this cube is also 4 cm.

The volume of a triangular pyramid of base area (4 cm)² and height 4 cm is

V = (1/3)(base area)(height)

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8 0

3 years ago

Round your answer to the nearest hundreth

Juliette [100K]

Answer:

Step-by-step explanation:

Area of a circle is found by using the equation:

$A = \pi r^{2}$

Radius = 1/2 (diameter) = 1/2 (16) = 8

So plug in:

$A = \pi (8)^{2}$

A = 64 $\pi$

A = 201.06193

Rounded A= 201. 06

5 0

3 years ago