" Given f (x) = 3x + 2 and g(x) = 4 – 5x, find (f + g)(x), (f – g)(x), (f × g)(x), and (f / g)(x).1. = [3x + 2] + [4 – 5x] = 3x + 2 + 4 – 5x. = 3x – 5x + 2 + 4. = –2x + 6. (f – g)(x) 2. = f (x) – g(x)= [3x + 2] – [4 – 5x] = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x– 2. 3. ...= (3x + 2)(4 – 5x) = 12x + 8 – 15x2 – 10x. = –15x2 + 2x + 8. " - Google
Answer:
Hope this helps. If not let me know and I'll explain it better
.... I don't think anyone can answer that. We don't have anything to work off of.
27 divided by 3= 9
That's a division problem right?
Sorry,
Katie
Answer:
There are 8 males in the class and 42 females.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
x is the number of females.
y is the number of males.
Class of 50 students
This means that 
The number of females is 2 more than 5 times the number of males.
This means that 
So, finding y, the number of males:





Females:

There are 8 males in the class and 42 females.