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natita [175]
3 years ago
8

New Jersey-based Integra LifeSciences elected not to use personality tests to screen job applicants for achieving employee/compa

ny fit as the company was in a transition phase. It, however, was open to using personality tests in the future when the company would have gained some stability. In this case, which of the following, if true, would support this tentative decision of using personality tests?
a. Personality tests make applicants provide socially desirable responses.
b. Personality tests can categorize people and make them seem inflexible for adaptation to new changes taking place in an organization
c. Personality tests only work best when they are conducted in real settings or in believable circumstances
d. Personality tests usually result in biased outcomes Chart to Work to remaining)
Business
1 answer:
Bas_tet [7]3 years ago
6 0

Answer:

b. Personality tests can categorize people and make them seem inflexible for adaptation to new changes taking place in an organization

Explanation:

A personality test can be defined as a means of assessing and defining peoples personalities. Such tests involves using certain techniques to measure the different traits and patterns that people show at different situations that may arise.

in this question, based on the fact that this organization is in a transitional stage, it is best that they do not use a personality test. A personality test would only put the workers in categories, that is it would only settle them for just a particular role. putting them in categories is just like telling them that they can only fit into one role in the organization. so there would be no flexibility.

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Each of 16 students measured the circumference of a tennis ball by four different methods, which were:
antoniya [11.8K]

Question Continuation

a. Compute the mean measurement for each method.

b. Compute the median measurement for. each method.

c. Compute the 20% trimmed mean measurement for each method.

Answer:

a. Mean

Mean A = 22.675

Mean B = 20.71875

Mean C = 21.0125

Mean D = 20.86875

b. Median

Median A = 23.45

Median B = 20.45

Median C = 21.0

Median D = 20.7

c. 20% Trimmed Mean

Trimmed Mean A = 23.14

Trimmed Mean B = 20.73

Trimmed Mean C = 21.04

Trimmed Mean D = 20.75

Explanation:

a.

Mean = Σx/n

Where Σx= Summation of entries in each method

n = 16

Mean of Method A = (18.0 + 18.0 +18.0 + 19.0 + 22.0 + 22.0 + 22.5 + 22.9 + 24.0 + 24.0 + 25.0 +25.0 + 25.0 + 25.0 + 26.0 +26.4)/16

Mean A = 362.8/16

Mean A = 22.675

Mean of Method B = (18.8 + 18.9 + 18.9 + 19.8 + 20.1 + 20.4 + 20.4 + 20.4 + 20.6 + 20.5 + 21.2 + 21.9 + 22.0 + 22.0 + 22.0 + 23.6)16

Mean B = 331.5/16

Mean B = 20.71875

Mean of Method C = (20.2 + 20.5 + 20.5 + 20.7 + 20.8 + 20.9 + 21.0 + 21.0 + 21.0 + 21.0 + 21.0 + 21.5 + 21.5 + 21.5 + 21.5 + 21.6)/16

Mean C = 336.2/16

Mean C = 21.0125

Mean of Method D = (20.0 + 20.0 + 20.0 + 20.2 + 20.2 + 20.5 + 20.5 + 20.7 + 20.7 + 20.7 + 21.0 + 21.5 + 21.5 + 21.6 + 22.1 + 22.3)/16

Mean D = 333.9/16

Mean D = 20.86875

b.

Median is the number(s) at the middle

Since the total number of points for each method is 16 and this is an even number we need to calculate the median as the average between the 8th and the 9th position of the data ordered from the smallest to the largest. If we do this we have that:

Method A

Arranged Data: 18.0, 18.0, 18.0, 19.0, 22.0, 22.0, 22.5, 22.9, 24.0, 24.0, 25.0, 25.0, 25.0, 25.0, 26.0, 26.4

The 8th and 9th data are: 22.9 and 24.0

Median = (22.9 + 24.0/2

Median = 46.9/2

Median A = 23.45

Method B

Arranged Data: 18.8, 18.9, 18.9, 19.8, 20.1, 20.4, 20.4, 20.4, 20.5, 20.6, 21.2, 21.9, 22.0, 22.0, 22.0, 23.6

The 8th and 9th data are: 20.4 and 20.5

Median = (20.4+20.5)/2

Median = 40.9/2

Median B = 20.45

Method C

Arranged Data: 20.2, 20.5, 20.5, 20.7, 20.8, 20.9, 21.0, 21.0, 21.0, 21.0, 21.0, 21.5, 21.5, 21.5, 21.5, 21.6

The 8th and 9th data are: 21.0 and 21.0

Median = (21.0 + 21.0)/2

Median = 42.0/2

Median C = 21.0

Method D

Arranged Data: 20.0, 20.0, 20.0, 20.2, 20.2, 20.5, 20.5, 20.7, 20.7, 20.7, 21.0, 21.5, 21.5, 21.6, 22.1, 22.3

The 8th and 9th data are: 20.7 and 20.7

Median = (20.7+20.7)/2

Median = 41.4/2

Median D = 20.7

c.

The trimmed mean by 20% means that we'll calculate mean by removing the 20% from each of the tails.

20% of 16 = 3.2 (Approximated to 3)

So we need to remove 3 observations from both ends of the data.

Method A becomes

19.0, 22.0, 22.0, 22.5, 22.9, 24.0, 24.0, 25.0, 25.0, 25.0

Trimmed Mean A = (19.0+22.0+22.0+22.5+ 22.9+24.0+24.0+25.0+ 25.0+ 25.0)/10

Trimmed Mean A = 231.4/10

Trimmed Mean A = 23.14

Method B becomes

19.8, 20.1, 20.4, 20.4, 20.4, 20.6, 20.5, 21.2, 21.9, 22.0

Trimmed Mean B = (19.8+20.1+20.4+ 20.4+ 20.4+20.6+20.5+21.2+21.9+22.0)/10

Trimmed Mean B = 207.3/10

Trimmed Mean B = 20.73

Method C becomes

20.7, 20.8, 20.9, 21.0, 21.0, 21.0, 21.0, 21.0, 21.5, 21.5

Trimmed Mean C = (20.7+ 20.8+ 20.9+ 21.0+ 21.0+ 21.0+21.0+, 21.0+, 21.5+21.5)/10

Trimmed Mean C = 210.4/10

Trimmed Mean C = 21.04

Method D becomes

20.2, 20.2, 20.5, 20.5, 20.7, 20.7, 20.7, 21.0, 21.5, 21.5

Trimmed Mean D = (20.2+, 20.2+20.5+, 20.5+ 20.7+ 20.7+ 20.7 +, 21.0 +21.5 + 21.5)/10

Trimmed Mean D = 207.5/10

Trimmed Mean D = 20.75

7 0
3 years ago
On January 1, 2011, Ozark Minerals issued $10 million of 9%, 10-year convertible bonds at 101. The bonds pay interest on June 30
horsena [70]

Answer:

Explanation:

Bonds are corporate debt units that are issued by firms inform of financial securities and  are traded as tradeable assets. It is basically referred to as a fixed income instrument since bonds conventionally are paid a certain fixed amount of interest rate (coupon) to its respective debtholders.

going by the question Upon issuance, Ozark should

Credit premium on bonds payable $100,000

Because face value of bonds =  $10 million but issue price is  $10 million * 101 % i.e $ 10100000

So, premium = 10100000 - 10000000 = $ 100000

5 0
3 years ago
Read 2 more answers
Nix’It Company’s ledger on July 31, its fiscal year-end, includes the following selected accounts that have normal balances (Nix
PilotLPTM [1.2K]

Answer and Explanation:

The Journal entries are shown below:-

1. Sales Dr, $161,600

          To Income summary $161,600

(Being To close a temporary account with credit balances is recorded)

2. Income summary Dr, $176,650

      To Sales discount $4,300

       To Sales return and allowance $5,100

        To Cost of good sold $111,050

        To Depreciation expenses $11,700

        To Salaries expenses $39,500

        To Miscellaneous expenses $5,000

(Being to close a temporary account with a debit balance is recorded)

Working note:-

shrinkage based on physical count = $44,800 - $42,950

= $1,850

Cost of good sold = $109,200 + $1,850

= $111,050

5 0
3 years ago
The following is correct statement related to the activity-based costing and traditional costing system, except:
kati45 [8]
The answer is D. Please don't discriminate if I'm wrong.
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4 0
3 years ago
Lyons Company deducts insurance expense of $210,000 for tax purposes in 2021, but the expense is not yet recognized for accounti
Goryan [66]

Answer:

$42,000

Explanation:

Deferred tax liability can be defined as the tax liability which has been due for the current period but has not yet been paid such as installment sales receivable.

Insurance expense of $210,000

Tax rate of 20%

( $210,000 × .20 )

=$42,000

Therefore the amount of the deferred tax liability at the end of 2021 will be $42,000

6 0
3 years ago
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