12x^2y^2+2xy-2 with problems like these use the app “Photomath” it will help you a lot.
-78
Step-by-step explanation:
(7-8)(78)
(-1)(78)=-78
Answer:
1/3 or 0.33
Step-by-step explanation:
Hope it helps
LMK if it does and weather it is wrong or right
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
A, B, and D all only have one solution.
Step-by-step explanation:
