Answers:
1. 7500 J; 3800 J/g
Step-by-step explanation:
1. Joules gained by water
q = mcΔT
Data:
m = 100 g
C = 4.184 J·°C⁻¹g⁻¹
ΔT = 18 °C
Calculation:
q = 100 × 4.184 × 18 =7500 J
2. Joules per gram of Pringle
Energy gained by water = energy lost by Pringle
q = -mΔH
7500 J = -1.984 g × ΔH
ΔH = -7500 J/1.984 g = -3800 J/g
Pringles contain 3800 J of food energy per gram.
The balanced reaction is:
<span>4 Al + 3 O2
--> 2 Al2O3</span>
Each Aluminum atom wants to lose 3 electrons to become
isoelectronic with Oxygen. Each Oxygen on the other hand wants to gain 2
electrons. Since the reaction shows 6 Oxygen atoms in the product and each want
to gain 2 electrons, therefore a total of 12 electrons are transferred. Since
the problem ask for the electrons transferred per formula unit, hence:
<span>6 electrons (ANSWER)</span>
Answer:
Explanation:
The alkene reactions in general are addition or oxidation reactions. For the addition reaction, we have to take into account that some of them are marknonikov and other anti-markovnikov. Also for the addition reaction, we will have to take into account if we will have anti or syn products. In the oxidation reaction, we have to know the specifics for each reaction. If the reaction can go to the highest oxidation level, is the double bond is broken, etc.
Each reaction has its <u>specific characteristics</u> (see figures 1 and 2).
Mass of Al₂(SO₄)₃ : 4.822 g
<h3>Further explanation </h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
2AlCl₃ + 3(NH₄)₂SO₄⇒Al₂(SO₄)₃+ 6NH₄Cl
MW AlCl₃ :133,34 g/mol
MW (NH₄)₂SO₄ : 132,14 g/mol
MW Al₂(SO₄)₃ : 342,15 g/mol
mol AlCl₃

mol (NH₄)₂SO₄

Limitng reactants (ratio mol : coefficient = the smaller)
AlCl₃ : (NH₄)₂SO₄ =

(NH₄)₂SO₄ ⇒ limiting reactants
So mol Al₂(SO₄)₃ from (NH₄)₂SO₄

mass Al₂(SO₄)₃

with 54.2% yield, the mass of Al₂(SO₄)₃

It would be d.
Reason being said...
the electron configuration normally goes like this...
1s2 2s2 2p6 3s2 3p6 4s2....
until you hit the transition metals..remember those have a special rule..
even though you are in the 4 sublevels for the orbitals ... it goes down 1
Making it 3d..(1,2,3,4,5,6,7,8,9,10)
Going on...
at 5s2 then, 4d1, 4d2, 4d3, 4d4, etc..
at 6s2 then, 5d1, 6d2, 6d3, 6d4, etc..
Thus, D orbital is your answer.