The atom or an ion which loses electron /electrons is called reducing agent.
Whole moving across a period from left to right metallic character decreases, therefore reducing power element decreases.
Answer:
it is possible to remove 99.99% Cu2 by converting it to Cu(s)
Explanation:
So, from the question/problem above we are given the following ionic or REDOX equations of reactions;
Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V
Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V
In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:
Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.
Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.
Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.
Thus, ΔG° = - 92640.
This is less than zero[0]. Therefore, it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.
Answer:
Density, 
Explanation:
It is given that the density of liquid mercury is 13.6 g/mL. We need to convert the density into lb/in³.
We know that,
2.205 lbs= 1 kg
1 g = 0.0022 lb
1 mL = 0.0610 in³
So, the density of liquid mercury is 
.
Answer:
the ans is in the picture with the steps
(hope it helps can i plz have brainlist :D hehe)
Explanation:
Answer:
B, adding an indicator to a solution to test its acidity
Explanation:
