<h3>
Answer:</h3>
19.3 g/cm³
<h3>
Explanation:</h3>
Density of a substance refers to the mass of the substance per unit volume.
Therefore, Density = Mass ÷ Volume
In this case, we are given;
Mass of the gold bar = 193.0 g
Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm
We are required to get the density of the gold bar
Step 1: Volume of the gold bar
Volume is given by, Length × width × height
Volume = 0.50 cm × 10.0 cm × 2.0 cm
= 10 cm³
Step 2: Density of the gold bar
Density = Mass ÷ volume
Density of the gold bar = 193.0 g ÷ 10 cm³
= 19.3 g/cm³
Thus, the density of the gold bar is 19.3 g/cm³
Answer:
<em>I</em><em> think</em><em> option</em><em> </em><em>(</em><em>b)</em><em> </em><em>is</em><em> right</em><em> answer</em>
Answer:
The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.
Explanation:
Let the mass of silver ornament be x.
Mass of gold polished on an ornament = 1% of x= 0.1 x
Moles of silver =
Number of atoms = 
Where : 
= Avogadro number
Moles of gold =
Silver atoms =
Gold atoms =
The ratio of the number of atoms of gold and silver in the ornament:
= 197 : 1080
Answer:
i think its b but i could be wrong
Explanation:
You will know;
1. know what products are
2. know how they work
