$Use:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\\\(ab)^n=a^nb^n$

$\left(\dfrac{a^{-3}b}{a^{-5}b^3}\right)^{-3}=\left(a^{-3-(-5)}b^{1-3}\right)^{-3}=\left(a^{-3+5}b^{-2}\right)^{-3}=\left(a^2b^{-2}\right)^{-3}\\\\=(a^2)^{-3}(b^{-2})^{-3}=a^{2(-3)}b^{-2(-3)}=a^{-6}b^6=\dfrac{b^6}{a^6}$

7 0

3 years ago

Which value of x makes the equation -5(x-3)=-25

Mnenie [13.5K]

Answer:

x=8

Step-by-step explanation:

-5(x-3)=-25

Divide each side by -5

-5/-5(x-3)=-25/-5

x-3 = 5

Add 3 to each side

x-3+3 = 5+3

x = 8

4 0

3 years ago

Read 2 more answers

Two times a number minus six another number is six. Two times the first number added to three times the other number is twenty f

expeople1 [14]

Answer:

First Number: 2

Step-by-step explanation:

You need to work backwards, as an algebraic equation.

24 ÷ 3 = 8

8 ÷ 2 = 4

4 × 2 = 8

8 - 6 = 2

The first number is 2.

- Educationist

4 0

2 years ago