1/a
The b^-3 in the denominator and numerator cancel out
I got 75582.
Explanation:
First, group the 40 identical candies into 20 pairs. It doesn't matter how since the candies are identical. This grouping will ensure that any assigment will contain at least two candies.
Then think of the 20 groups a 20 beads on a string. We are looking to place 11 separators between them to obtain 12 segments, each with a varying number of beads between them. How many ways are there to place 11 separators to 19 potential spaces between beads? The asnwer is 
Answer:
9/10
Step-by-step explanation:
the answer for this question is cot theta is equal to 24/ 7
Given:
a square with an area of a² is enlarged to a square with an area of 25a².
The side length of the smaller square was changed when The side length was multiplied by 5.
Area = (1a)² = a²
Area = 1a * 5 = 5a ⇒ (5a)² = 25a²