Answer:
Step-by-step explanation:
2 cos(A+45)cos (B-45)
=2[cos A cos 45-sin A sin 45][cos B cos 45+sin B sin 45]
=2[cos A ×1/√2-sin A ×1/√2][cos B×1/√2+sin B×1/√2]
=2[1/√2(cos A-sin A)][1/√2(cos B-sin B]
=2×1/√2×1/√2 (cos A-sin A)(cos B+sin B)
=cosA cos B+cos A sin B-sin A cos B-sin A sin B
=cos A cos B-sin A sin B-(sin A cos B-cos A sin B)
=cos (A+B)-sin (A-B)
i think there should be A in place of B.
then
=cos (A+A)-sin (A-A)
=cos 2A-sin 0
=cos 2A
as sin 0=0
Answer:
(4,-1)
Step-by-step explanation:
Hopfully this helps you out!!
Sin 60⁰= x/10
x=10*sin 60⁰
x=10*(√3/2)=5√3
x=5√3
Answer is x=5√3.
The LCM of 24 and 30 is 120.
<u>Given</u>:
Given that the circle with center O.
The radius of the circle is OB.
The chord of the circle O is PQ and the length of PQ is 12 cm.
We need to determine the length of the segment PA.
<u>Length of the segment PA:</u>
We know that, "if a radius is perpendicular to the chord, then it bisects the chord and its arc".
Thus, we have;

Substituting the value PQ = 12, we get;


Thus, the length of the segment PA is 6 cm.
Hence, Option d is the correct answer.