Answer:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
Step-by-step explanation:
We can demonstrate that Circle R is similar to Circle Q by translating the center of the former one to the center of latter one. Meaning that every point of circle R experiments the same translation. Vectorially speaking, a translation is defined by:
(1)
Where:
- Original point.
- Translated point.
- Translation vector.
If we know that and , then the translation vector is:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
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1x68
2x34
4x17
Hope that helps
Answer:
x=34, y=-28, z=-46
Step-by-step explanation:
because opposite angles of parallelograms are congruent: -3y-3=81 => y=-28. because internal angles of quadrilateral sum to 360°: 81+-3(-28)-3+3x-3-2z+7=360 => 3x-2z=194 => z=3/2x-97. because opposite angles of parallelograms are congruent: -2z+7=3x-3. substitute z=3/2x-97: -2(3/2x-97)+7=3x-3 => x=34. z=3/2(34)-97=-46