3D shape practice. I'm stuck in this problem. Pleas help.
1 answer:
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Answer:
A
Step-by-step explanation:
Given
y = 2x² - 3x + 1
To find the zeros let y = 0, that is
2x² - 3x + 1 = 0
Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × 1 = 2 and sum = - 3
The factors are - 2 and - 1
Use these factors to split the x- term
2x² - 2x - x + 1 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) - 1(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x - 1) = 0
Equate each factor to zero and solve for x
2x - 1 = 0 ⇒ 2x = 1 ⇒ x =
x - 1 = 0 ⇒ x = 1
Answer:
Step-by-step explanation:
To write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to write.
To add the polynomials you need to:
Remove parentheses
Group like terms
Add similar elements