Question

Solve:d="TexFormula1" title=" \frac{dy}{dx} = {x}^{3} + 5x - 18" alt=" \frac{dy}{dx} = {x}^{3} + 5x - 18" align="absmiddle" class="latex-formula">
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Answer 1

$y = \frac{1}{4} {x}^{4} + \frac{5}{2} {x}^{2} - 18x + k$

Step-by-step explanation:

$dy = ( {x}^{3} + 5x - 18)dx$

Integrating the above expression, we get

$y = \int( {x}^{3} + 5x - 18)dx$

$= \frac{1}{4} {x}^{4} + \frac{5}{2} {x}^{2} - 18x + k$

where k is the constant of integration