The two non negative real numbers with a sum of 64 that have the largest possible product are; 32 and 32.
<h3>How do we solve the nonnegative real numbers?</h3>
Let the two numbers be x and y.
Thus, if their sum is 64, then we have;
x + y = 64
y = 64 - x
Their product will be;
P = xy
Putting (64 - x) for y in the product equation we have;
P = (64 - x)x
P = 64x - x²
Since the product is maximum, let us find the derivative;
P'(x) = 64 - 2x
At P'(x) = 0, we have;
64 - 2x = 0
2x = 64
x = 64/2
x = 32
Thus; y = 64 - 32
y = 32
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No, because both can be divided by two. in simplist form it is 3 1/9
Answer:
A, 2/3
Step-by-step explanation:
you rise 2 and run 3
Answer:
the one you picked was right.
Step-by-step explanation:
if 63° was the angle and the 12 was the side then "x" will be one the bottom. then you flip the fraction meaning 1/sin63° and x/12 and then multiply 12 on both sides. you will be left with x = 12/sin63°. sorry if that doesn't make sense
If you add each cost together the price is 47.45
Hope this helps :)
