Answer:
{36, 38, 40, 42, 44}
Step-by-step explanation:
You are implying that you are adding up 5 consecutive numbers, and should use the word "add" or the word "sum."
"The sum of 5 consecutive odd numbers is 200" leads to:
x + (x+2) + (x+4) + (x+6) + (x+8) = 200. Note how each number is 2 more than the number preceding it. In this way you can guarantee that all of the 5 numbers are odd.
Summing up, we get 5x + 20 = 200, or 5x = 180.
Dividing both sides by 5, we get x = 36.
Then the 5 consecutive integers are
{36, 38, 40, 42, 44}. These add up to 200.
Unfortunately, these are consecutive EVEN numbers, not odd numbers.
Please ensure that you have copied down this problem correctly.
Answer:
1) x=10
2) x=6
3) x=13
Step-by-step explanation:
1) 15x-17+4x+7=180
19x-10=180
19x=190
x=10
2) 13x+5=16x-13
5+13=16x-13x
18=3x
x=6
3) 9x+7=11x-19
7+19=11x-9x
26=2x
x=13
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function 
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
Answer:
W =<u> P - 2L </u>
2
Step-by-step explanation:
perimeter P = 2L + 2W
P - 2L = 2W
W =<u> P - 2L </u>
2
