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ElenaW [278]
4 years ago
6

You have to work on Distributive property 12(y+2)

Mathematics
1 answer:
Free_Kalibri [48]4 years ago
7 0

Answer:

12y + 24

Step-by-step explanation:

12 (y + 2) ---> 12y + 24

I don't know if I'm missing something but uh... it was simple? Tell me if I missed something.

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11. You expect to have the given amount in an account with the given terms. Find how much you can withdraw periodically in order
Orlov [11]

This is a question on Present Value of Annuity and we seek the periodic withdrawal.

\begin{gathered} F\text{VA}=\text{PMT(}\frac{(1+\frac{i}{m})^{nm}-1}{\frac{i}{m}}) \\ \text{Therefore, PMT=}\frac{FVA}{(\frac{(1+\frac{i}{m})^{nm}-1}{\frac{i}{m}})} \end{gathered}

where:

FVA = Future value of annuity

PMT = Periodic Withdrawal

i = interest/discount rate

n = no of years

m = no of compundings per interest period

\text{PMT=}\frac{300000}{(\frac{(1+\frac{0.0445}{365})^{22\times365}-1}{\frac{0.0445}{365}})}=22.01

PMT = $22.01

8 0
1 year ago
28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. the water level rises to the 49.10 mL mark. F
Alika [10]
Density=mass/volume.
1) we have to calculate the iron volume in liters.
iron volume=second level - first level=49.10 ml-45.50 ml=3.6 ml
3.6 ml=3.6 ml(1 liter / 1000 ml)=0.0036 liters 

2) we calculate the mass iron in kg.
28.5 g=28.5 g(1 kg /1000 g)=0.0285 kg.
2) we calculate the density of iron.
density=0.0285 kg / 0.0036 liters=7.92 kg/L

7.92 kg/l=7.92 kg/L(1000 g/1Kg)(1000 cm³/1 L)=7.92 g/cm³.

answer: From this information the Iron density is 7.92 Kg/L or  7.92 g/cm³.
5 0
4 years ago
If AD = 6 cm, DB = 4.2 cm, AB = 8.7 cm, and ED = 3.9 cm, what is the measure of DC?
marshall27 [118]
You cannot work this out without the angles

4 0
3 years ago
Find the missing side length of the triangle 48 units 14 units​
Tpy6a [65]

Answer:

what are the options? I would say something like 50-60

5 0
3 years ago
ALL OF THEM FOR BRAINLIEST
Pepsi [2]

Answer:

1. 8/9

2. 8575

3. 1/54

4. -225

Goodluck:)

8 0
3 years ago
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