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Aleks04 [339]
2 years ago
8

Please solve this correctly

Mathematics
1 answer:
dusya [7]2 years ago
6 0
B.16.7%. This is the right answer
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Please help! first person gets brainliest!
White raven [17]

Answer:

simple event and dependent event

Step-by-step explanation:

not needed

6 0
2 years ago
Which value for x makes this open sentence true? 5 + 5 ● x = x² + 3²
Angelina_Jolie [31]
The answer your looking for here is 1
5 0
2 years ago
Write the equation of the quadratic function in standard form represented by the graph.
algol13

Answer:

y = x^2 +6x+8

Step-by-step explanation:

First find the zeros, -4 ,-2

y =a (x - -4) (x - -2)

y = a(x+4)(x+2)

Then it is multiplied by a constant so pick a point on the curve and solve for the constant

We will use (0,8)

8 = a(0+4)(0+2)

8 = a(8)

a =1

y = (x+4)(x+2)

Writing in standard form

FOIL

y = x^2 +2x+4x+8

y = x^2 +6x+8

6 0
3 years ago
Sec^6x (secxtanx) - sec^4x (secxtanx) = sec^5x tan^3x
Olegator [25]
Let E the expression of the left side of the equation:

E=\sec^6(x) (\sec (x)\tan (x)) - \sec^4(x) (\sec (x)\tan (x))\\\\
E=\sec^7(x)\tan(x)-\sec^5(x)\tan(x)\\\\
E=\sec^5(x)\tan(x)(\sec^2(x)-1)

We must know that \tan^2(x)+1=\sec^2(x)\iff \sec^2(x)-1=\tan^2(x). So, using in the equation above:

E=\sec^5(x)\tan(x)(\underbrace{\sec^2(x)-1}_{\tan^2(x)})\\\\
E=\sec^5(x)\tan(x)(\tan^2(x))\\\\
\boxed{E=\sec^5(x)\tan^3(x)}

Then, the equation is true.
3 0
3 years ago
⊂(T-T)⊃_⊂(T-T)⊃_⊂(T-T)⊃_⊂(T-T)⊃_⊂(T-T)⊃_⊂(T-T)⊃_⊂(T-T)⊃_⊂(T-T)⊃
kicyunya [14]

Answer:

i think its C

i can't really see that well

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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