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Viktor [21]
3 years ago
13

Write an equation in slope intercept form of the line with the given parametric equations x=8t+3 y=9t+3

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

The slope intercept equation of the line is:

<u>  y = (9/8)x - (3/8)</u>

Step-by-step explanation:

- They give us 2 parametric equations to arrive at y = mx + b (Slope intersection equation)

1. X = 8t + 3

2. Y = 9t + 3

- We first convert in terms of t to compare both equations:

1. x = 8t + 3

x - 3 = 8t

t = (x - 3) / 8

- Same for the following:

3. y = 9t + 3

y - 3 = 9t

t = (y - 3) / 9

- Now equating by comparing both equations, we will find y:

(x - 3) / 8 = (y - 3) / 9

9x -27 = 8y -24

9x - 3 = 8y

- Clearing and comparing both parameters gives us:

 y = (9/8)x - 3/8

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Answer:

\pink{\boxed{{\colorbox{white}{Answer}}}}

\purple {\overline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}

In the figure, the slope of mid-segment DE is -0.4. The slope of segment AC is?

A.) 0.4

B.) -0.4

C.) 2

D.) -2

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Step-by-step explanation:

\pink{\boxed{{\colorbox{white}{- MsTiyana}}}}

# i hope it helps you

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8 0
2 years ago
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Answer:

Exact form : x = +_2 squareroot 11+5

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I hope this helps you out! :)

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Natalia goes to the bookstore with $25.00. She buys 4 magazines for $3.25 each and a comic book for $5.75. How much money does s
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Step-by-step explanation:

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The x-intercept of the graph is the x-point where graph touches the x-axis. ... Here graph touches the x-axis two times. (c) (–1, 2) and (1, 0): x-intercept are -1 and -1.
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2 years ago
In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.
ankoles [38]
<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

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By Pythagorean theorem, for triangle NQP:

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Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

3 0
3 years ago
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