If you put 5 which means its 2 1/2 ( I think) Because two 1/2 makes one.
Well we are starting with a full pitcher(1)
1/4=2/8 & 1/8+2/8=3/8
then you subtract that from 1
1-3/8=5/8
Answer:
There is a 2/3 probability that the other side is also black.
Step-by-step explanation:
Here let B1: Event of picking a card that has a black side
B2: Event of picking a card that has BOTH black side.
Now, by the CONDITIONAL PROBABILITY:

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.
⇒ P (B1 ∩ B2) = 1 /3
Also, Out if total 6 sides of cards, 3 are BLACK from one side.
⇒ P (B1 ) = 3 /6 = 1/2
Putting these values in the formula, we get:

⇒ P (B2 / B1) = 2/3
Hence, there is a 2/3 probability that the other side is also black.
Answer:
{-5,-4,2,4}
Step-by-step explanation:
the domain is which x-values are included so use each of the x-values for each pair. Make sure if there are reapeats that you only write them once.
Answer:
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