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Dima020 [189]
3 years ago
13

Solve for X

Mathematics
1 answer:
labwork [276]3 years ago
8 0

C, x is greater than or equal to 2

Step-by-step explanation:

Both equations have X equaling to 2

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Given that BD is the median of AABC and that AABC is isosceles, congruence postulate SSS can be used to prove which of the follo
marusya05 [52]

Answer:

B.

Step-by-step explanation:

Because of isosceles triangle, AB = CB.

Because of the median, AD = CD.

Because of congruence of segments being reflexive, BD = BD.

By SSS, the triangles BAD and BCD are congruent.

Answer: B.

7 0
2 years ago
3). Find the area of a triangle with a height of 15 cm and a base of 24 cm
tresset_1 [31]

Answer:

answer is 360

Step-by-step explanation:

multiply length times width

3 0
3 years ago
Let f(x) = (x − 3)−2. Find all values of c in (1, 7) such that f(7) − f(1) = f '(c)(7 − 1). (Enter your answers as a comma-separ
Sidana [21]

Answer:

This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3

Step-by-step explanation:

The given function is

f(x)=(x-3)^{-2}

When we differentiate this function with respect to x, we get;

f'(x)=-\frac{2}{(x-3)^3}

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)

This implies that;

0.06-0.25=-\frac{2}{(c-3)^3} (6)

-0.19=-\frac{12}{(c-3)^3}

(c-3)^3=\frac{-12}{-0.19}

(c-3)^3=63.15789

c-3=\sqrt[3]{63.15789}

c=3+\sqrt[3]{63.15789}

c=6.98

If this function satisfies the Mean Value Theorem, then f must be continuous on  [1,7] and differentiable on (1,7).

But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.

 

3 0
3 years ago
How do ypu find the area of 1/4 of a circle?
julia-pushkina [17]
First find the area of the circle then divide it by 4
6 0
3 years ago
Point C has the coordinates (–1, 4) and point D has the coordinates (2, 0). What is the distance between points C and D?
Bad White [126]

Answer:

5

Step-by-step explanation:

Use the distance formula d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

insert the numbers into the formula d=\sqrt{(2+1)^2+(0-4)^2}

2+1=3 and 0-4=-4

3^2 =9 and -4^{2} = 1

9+16=25

the square root of 25 is 5

6 0
4 years ago
Read 2 more answers
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