Answer:
A. y = -3/2x + 1
B. y = -5/3x + 10
C. y = -x + 6/5
Step-by-step explanation:
A. You just have to isolate the y so divide by 4: y = -3/2x + 1
B. 3y = -5x + 30
Divide by 3: y = -5/3x + 10
C. -5x + 6 = 5y
Divide by 5: -1x + 6/5 = y OR y = -x + 6/5
Answer:
c. isosceles
Step-by-step explanation:
the base angles are the same
Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
This equation can be written as
(v-8)(v+5)/ (v-8)(v-3)
= v+5/v-3