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AURORKA [14]
3 years ago
10

If the measure of 5 is 63 degrees what is the measure of 3

Mathematics
1 answer:
finlep [7]3 years ago
4 0
37.8 because you multiply 3 by 12.6 i got 12.6 by dividing 63 by 5
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How do I find the range of this rational function, how do I do the steps in order to find it, please help!!!​
Sindrei [870]

Answer:

Range= (0,∞) and (-∞,0)

Step-by-step explanation:

Theres no real process to finding this out you just look at what type of function you have, your graph and your asymptote. We can see that the parts above the asymptote go up and towards ∞ and the part below goes down to -∞ but they can not cross 0

8 0
3 years ago
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Write an equation of the graph:<br> y = |x| translated half a unit upward
Rudik [331]

Answer: y = I x l + 1/2

Step-by-step explanation:

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3 years ago
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1/4 of all telephones at the office have built-in speaker phones 1/2 of the phone with the built in speaker phones have conferen
neonofarm [45]

Answer:

1/8

Step-by-step explanation:

1/2 of 1/4 is 1/8

7 0
3 years ago
Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

5 0
2 years ago
WILL MARK BRAINLIEST
Levart [38]

Answer:

Part 1:

The solution set of the system of equations is x = 1, y = 1

Part 2:

The solution set is x = 1, y = 1

Part 3:

The similarity of the system of equations in Parts 1 and 2 is that they have the same solution set

The difference of the system of equations in Parts 1 and 2 is that they are arranged differently

Step-by-step explanation:

Part 1:

The system of equation is given as follows;

2·x + y = 3...(1)

x = 2·y - 1...(2)

The above system of equations can be written in terms of the variable, y, as follows;

For equation (1), we have;

y = 3 - 2·x

For equation (2), we have;

y = (x + 1)/2

From the attached graph created with Microsoft Excel, we have;

The solution set (the point of intersection) of the system of equations is x = 1, y = 1

To accurately find the common solution, we have;

(x + 1)/2 = 3 - 2·x

x + 1 = 2·(3 - 2·x) = 6 - 4·x

x + 1 = 6 - 4·x

x + 4·x = 6 - 1

5·x = 5

x = 5/5 = 1

x = 1

Therefore, y = 3 - 2·x = 3 - 2× 1 = 1, at the common solution

Part 2:

y = -2x + 3

x - 2y = -1

∴ x = 2y -1

y = -2(2y -1) + 3

y = -4y + 2 + 3

5y = 5

y = 1

x = 2y - 1 = 2 - 1 = 1

x = 1

The solution set is x = 1, y = 1

Part 3

The system of equations are similar in terms of their solution

The system of equations are different in terms of their arrangement

6 0
2 years ago
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