Suppose you need to prepare 138.1 mL of a 0.190 M aqueous solution of NaCl. What mass, in grams, of NaCl do you need to use to m
1 answer:
You might be interested in
Answer:
When C1 is labeled in glucose, it ends up in the methyl group of pyruvate.
Aldolase cleaves a hexose into two trioses.
[See the image attached].
Asterisk indicates the label.
When C1 is labeled in glucose, it ends up in the carboxyl group of pyruvate.
Answer:
The chemistry will need 2*10⁶ moles of antimony trifluoride.
Explanation:
The balanced reaction is:
3 CCl₄ (g) + 2 SbF₃ (s) → 3 CCl₂F₂(g) + 2 SbCl₃ (s)
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- CCl₄: 3 moles
- SbF₃: 2 moles
- CCl₂F₂: 3 moles
- SbCl₃: 2 moles
You can apply the following rule of three: if by reaction stoichiometry 3 moles of freon are produced by 2 moles of antimony trifluoride, 3*10⁶ moles of Freon are produced from how many moles of antimony trifluoride?
moles of antimony trifluoride= 2*10⁶
<u><em>The chemistry will need 2*10⁶ moles of antimony trifluoride.</em></u>