<span>C2H4O + H2O = C2H6O2
moles water = 18 g/ 18.02 g/mol=.998
the ratio is 1 : 1 : 1
moles C2H4O needed = 0.998
mass C2H4O = 0.998 mol x 44.053 g/mol = 44.00 g
We require 44.00 g of ethylene oxide is needed to react with 18 g of water.</span>
<span>magnesium cations (Mg </span><span>2+</span>) and oxide anions (<span>O 2</span>−<span>)</span>
Answer:
(1) Bromination, (2) E2 elimination and (3) epoxidation
Explanation:
- In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with
- In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene
- In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane
- Full reaction scheme has been shown below
The Diesel cycle<span> is a combustion process of a reciprocating </span>internal combustion in the cylinders of the engine<span>. In it, </span>fuel<span> is ignited by heat generated during the compression of air in the combustion chamber, into which fuel is then injected and the exhaust from the combustion is pushed out the exhaust pipe or brought out by a turbo </span>
Answer:
The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements. Every element in the first column (group one) has one electron in its outer shell.
Explanation:
