1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andreas93 [3]
3 years ago
5

In 1906 Harden and Young, in a series of classic studies on the fermentation of glucose to ethanol and CO2 by extracts of brewer

's yeast, made the following observations.
(A) Inorganic phosphate was essential to fermentation; when the supply of phosphate was exhausted, fermentation ceased before all the glucose was used.
(B) During fermentation under these conditions, ethanol, CO2, and a sugar phosphate accumulated.
(C) When arsenate was substituted for phosphate, no sugar phosphate acumulated, but the fermentation proceeded until all the glucose was converted to ethanol and CO2.

Answer the following questions.

1. Which enzyme of glycolysis requires inorganic phosphate and therefore stops when no phosphate is available?
(a) glyceraldehyde 3-phosphate dehydrogenase
(b) phosphoglycerate mutase
(c) phosphofructokinase-1
(d) phosphoglycerate kinase

2. What sugar phosphate accumulates under these conditions?
(a) glucose 1,6-biphosphate
(b) glucose 1-phosphate
(c) fructose 1-phosphate
(d) fructose 1,6-biphosphate

3. Arsenate substitution for phosphate generated an acyl arsenate compound that immediately degraded. What glycolysis intermediate was a product of the spontaneous degradation of this acyl arsenate?
(a) glycerol 3-phosphate
(b) 3-phosphoglycerate
(c) dihydroxyacetone phosphate
(d) glyceraldehyde 3-phosphate
Chemistry
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

Answers to the (B) Part

1. A

2. D

3. B

Explanation:

Explanation of the (A) Part

a.

G-3-P, also known as Glyceraldehyde-3-Phozphate.

In the dehydrogenase process of G-3-P, phosphate is a compulsory requirement.

During this process, the G-3-P is hereby changed or converted into 1,3-bisphosphoglycerate in presence of NAD+ and Pi. Note that the exhaustion of Pi signal the end of the glycolysis process.

Because there's is glucose in abundance (excess), the glucose is thus, phosphorylated to ATP but no Pi gets released.

b.

During fermentation, CO₂ and Ethanol are produced. But if there's no fermentation of ethanol in the absence of oxygen (anaerobic condition) , the NADP+ will piled up.. So, no new NAD+ would be available for further glycolysis.

Pyruvate is converted to ethanol and CO2 to replenish NAD+ for glycolysis to proceed.

c.

The hexose phosphate is piled up or accumulated to fructose 1, 6 bisphosphate.

The point between the energy input reaction preceding it and the energy forming reaction after it serves as the intermediary of the reaction.

Because of unavailability of P, G-3-P is not broken down. Hence, the reaction will backflow to fructose 1, 6 bisphosphate, which is more stable.

You might be interested in
3.04 Quiz: Chemical Reactions 1 to 10 question
vaieri [72.5K]

Answer:

1. Chemical reactions

2.Substances

3. Properties

4. Precipitate

5. Light

6. Temperature

7. Color

8. Gas

Explanation:

During chemical reactions, new substances that possess new properties are formed. During the process of chemical reactions, evidences are found. Some of the evidences are formation of precipitate or light gel, production of gases and changes in color and temperature.

Chemical reactions start with the substances or compounds which are known as reactants. The reactants react to form new substances known as the products which possess new properties.

I only could help with 1 - 8 sorry.

5 0
3 years ago
PLEASE HELP!!
grandymaker [24]

Answer:

1. 136 °C.

2. 0.21 atm.

Explanation:

1. Determination of the new temperature in °C.

Initial volume (V1) = 1.35L

Final volume (V2) = 1.95L

Initial temperature (T1) = 283 K

Final temperature (T2) =...?

Using the Charles' law equation, the new temperature of the gas can be obtained as follow:

V1 /T1 = V2 /T2

1.35/283 = 1.95/T2

Cross multiply

1.35 × T2 = 283 × 1.95

1.35 × T2 = 551.85

Divide both side by 1.35

T2 = 551.85/1.35

T2 = 408.8 ≈ 409 K

Finally, we shall convert 409 K to °C. This can be obtained as follow:

T (°C) = T(K) – 273

T(K) = 409 K

T (°C) = 409 – 273

T (°C) = 136 °C

Therefore, the new temperature of the gas is 136 °C.

2. Determination of the new pressure.

Initial pressure (P1) = 1.34 atm

Initial volume (V1) = 267 mL

Final volume (V2) = 1.67 L

Final pressure (P2) =.?

Next, we shall convert 1.67 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

1.67 L = 1.67 L × 1000 mL / 1 L

1.67 L = 1670 mL

Therefore, 1.67 L is equivalent to 1670 mL.

Finally, we shall determine the new pressure of the gas as follow:

Initial pressure (P1) = 1.34 atm

Initial volume (V1) = 267 mL

Final volume (V2) = 1670 mL

Final pressure (P2) =.?

P1V1 = P2V2

1.34 × 267 = P2 × 1670

357.78 = P2 × 1670

Divide both side by 1670.

P2 = 357.78 / 1670

P2 = 0.21 atm.

Therefore, the new pressure of the gas is 0.21 atm.

3 0
3 years ago
For the purposes of determining electron configuration of ions, when electrons are added to a neutral atom, they will inhabit or
irga5000 [103]

Answer: Aufbau principle

Explanation: Aufbau Principle suggests that in filling electrons into orbitals, lower energy orbitals must be filled before higher energy orbitals.

8 0
3 years ago
Read 2 more answers
What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?
Sergeu [11.5K]

Answer:

\large \boxed{\text{b. 1.5 h}}

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463  h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}

4 0
3 years ago
Why is the cell membrane essential for cell homeostasis?
Nadya [2.5K]
Hello,

Here is your answer:

The proper answer to this question is option C "To allow waste to exit the cell"! The cell membrane controls the matieral that goes in and out of the cell!

Your answer is C.

If you need anymore help feel free to ask me!

Hope this helps!
3 0
3 years ago
Read 2 more answers
Other questions:
  • One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. to obtain a mixture of
    10·1 answer
  • 1. Find the elements magnesium, cesium, and nitrogen on the periodic table. a. What monoatomic ions would each form? Write this
    11·1 answer
  • If 50.0 g of KCl reacts with 50.0 g of O2 to produce KCLO3 according to the following equation how many grams of KCLO3 will be f
    9·1 answer
  • After some wood has completely burned in a fire, some of the matter that made up the wood has been destroyed.
    6·2 answers
  • Which element has chemical properties that are most similar to potassium?
    11·1 answer
  • Which organic compound has a triple bond?
    7·1 answer
  • Which of the following steps correctly converts 1.25 moles of fluorine to an equivalent mass of fluorine in grams? (5 points)
    10·1 answer
  • True or false, the four units that must always be used when using the ideal gas law are liters, atm, Kelvin, and grams
    13·1 answer
  • How does Barium obey the octet rule when reacting
    7·2 answers
  • If the heat capacity of an object is known, what other information will need to be known to calculate its specific heat capacity
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!