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Vanyuwa [196]
2 years ago
7

A study records the lengths of pregnancy (in days) of 500 women. The data is normally distributed with a mean of 266 days and a

standard deviation of 16 days. How many women in the study had a pregnancy between 250 days and 282 days in length?

Mathematics
1 answer:
VashaNatasha [74]2 years ago
4 0

Answer:

<em>371 women had their pregnancy between 250 days and 282 days in length.</em>

di po ako sure sa answer ko, but it is based on what I remembered.

Step-by-step explanation:

z=<u>532-266</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u>1</u><u>6</u><u> </u><u> </u>

√500

= 371.74 or 371

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tamaranim1 [39]
This can be solved by making an equivalent ratio.
The original ratio is what we know, 15 inches of wire for 90 cents.
In a ratio of inches of wire:cents, this would be 15:90.

Now for the equivalent ratio.
We don't know the number in the inches place but we do know it for the cents place.
Let's use x to represent inches of wire.
x:48 is our new ratio, and we need to find x.

Since x:48 and 15:90 are equivalent, that means the same thing that was done to 90 to get 48 has to be done to 15 to get the value of x, since the same thing must be applied to both sides.
We can find what 90 was divided by (which is what we'll have to divide 15 by) by dividing 90 by 48.
90 / 48 = 1.875

This means 48 • 1.875 = 90 and x • 1.875 = 15.
Since we don't know x though, we can isolate it by dividing both sides by 1.875.
x • 1.875 = 15
x • 1.875 / 1.875 = x
15 / 1.875 = 8
So x is 8.

Answer:
While you can be 15 inches of wire for 90 cents, you can buy 8 inches of wire for 48 cents at the same rate.
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3 years ago
Complete the square for:<br> 2x² - 36x - 16<br> show work.
nikklg [1K]

Answer:

Step-1 : Multiply the coefficient of the first term by the constant   1 • -8 = -8

Step-2 : Find two factors of  -8  whose sum equals the coefficient of the middle term, which is   -18 .

     -8    +    1    =    -7

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     -2    +    4    =    2

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Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

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