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2 years ago

Can you please answer the following

Mathematics

1 answer:

liberstina [14]2 years ago

7 0

Answer:

5. B

6. D

7. C

8. B

9. B

10. D

Step-by-step explanation:

I would write it but I have homework too

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The measurenicnt of the circumference of a circle is found to be 56 centimeters. The possible error in measuring the circumferen

BartSMP [9]

Answer:

(a) Approximate the percent error in computing the area of the circle: 4.5%

(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm

Step-by-step explanation:

(a)

First we need to calculate the radius from the circumference:

$c=2\pi r\\r=\frac{c}{2\pi } \\c=8.9 cm$

I leave only one decimal as we need to keep significative figures

Now we proceed to calculate the error for the radius:

$\Delta r=\frac{dt}{dc} \Delta c\\\\\frac{dt}{dc} = \frac{1}{2 \pi } \\\\\Delta r=\frac{1}{2 \pi } (1.2)\\\\\Delta r= 0.2 cm$

$r = 8.9 \pm 0.2 cm$

Again only one decimal because the significative figures

Now that we have the radius, we can calculate the area and the error:

$A=\pi r^{2}\\A=249 cm^{2}$

Then we calculate the error:

$\Delta A= (\frac{dA}{dr} ) \Delta r\\\\\Delta A= 2\pi r \Delta r\\\\\Delta A= 11.2 cm^{2}$

$A=249 \pm 11.2 cm^{2}$

Now we proceed to calculate the percent error:

$\%e =\frac{\Delta A}{A} *100\\\\\%e =\frac{11.2}{249} *100\\\\\%e =4.5\%$

(b)

With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

$\%e =\frac{\Delta A}{A} *100\\\\3\%=\frac{\Delta A}{249} *100\\\\\Delta A =7.5 cm^{2}$

Now we calculate the error for the radius:

$\Delta r= \frac{\Delta A}{2 \pi r}\\\\\Delta r= \frac{7.5}{2 \pi 8.9}\\\\\Delta r= 0.1 cm$

Now we proceed with the error for the circumference:

$\Delta c= \frac{\Delta r}{\frac{1}{2\pi }} = 2\pi \Delta r\\\\\Delta c= 2\pi 0.1\\\\\Delta c= 0.6 cm$

5 0

3 years ago

I need help on this problem! <br><br> g(h+2/3)=1 for h

Tju [1.3M]

Answer:

$g(h + \frac{2}{3} ) = 1 \\ \\ gh + \frac{2}{3} g = 1 \\ \\ gh = 1 - \frac{2}{3} g \\ \\ h = (1 - \frac{2}{3} g ) \div g \\ \\ h = (1 - \frac{2}{3} g ) \times \frac{1}{g} \\ \\ h = \frac{1}{g} - \frac{2}{3}$

I hope I helped you^_^

7 0

2 years ago

EASY 7TH GRADE MATH, WILL GIVE BRAINLIEST AND THANKS

Fudgin [204]

Answer:

D. 8

Step-by-step explanation:

2p=16

divide both sides by 2 to get p alone

p=8

7 0

2 years ago

Read 2 more answers

What is the value of x?<br><br>enter your answer in the box<br><br>X__

vfiekz [6]

<h3>Answer: x = 5</h3>

=====================

Work Shown:

Angle Bisector Theorem

9/(2x-1) = 15/3x

9*3x = 15(2x-1) ... cross multiply

27x = 30x-15

27-30x = 30x-15-30x ... subtract 30x from both sides

-3x = -15

-3x/(-3) = -15/(-3) .... divide both sides by -3

x = 5

6 0

3 years ago

Use the properties of logarithms to expand the following expression as much as possible. simplify any numerical expressions that

FinnZ [79.3K]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\ \quad \\\\
% Logarithm of rationals
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)
\\ \quad \\\\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-----------------------------\\\\
ln\left( \cfrac{6x^9}{y^5} \right)\implies ln(6x^9)-ln(y^5)\implies ln(6)+ln(x^9)-ln(y^5)
\\\\\\
ln(6)+9ln(x)-5ln(y)$

8 0

3 years ago