If angle a measured 55 degrees then,how much does angle b measure?

Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked h

Andrews [41]

Answer:

[0.9 months, 32.69 months]

Step-by-step explanation:

The mean is

$\bf \bar x=\frac{5+17+12+21+29}{5}=16.8$

The standard deviation is

$\bf s=\sqrt{\frac{(5-16.8)^2+(17-16.8)^2+(12-16.8)^2+(21-16.8)^2+(29-16.8)^2}{5}}=8.1092$

Now, we have to find two values a and b such that the area under the Normal curve with mean 16.8 and standard deviation 8.1092 between a and b equals <em>95% = 0.95 </em>

Using a spreadsheet we find these values are

a = 0.906

b = 32.694

<h3>(See picture) </h3>

and our 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program rounded to two decimal places is

[0.9 months, 32.69 months]

4 0

3 years ago

May someone please help me?

otez555 [7]

Answer:

x=8°

y=29°

Step-by-step explanation:

vertically opposite angles are equal

so 5x+9°=y+20°

therefore 5x-y=11°

Alternate angles are equal

so 4x+17°=y+20°

therefore 4x-y=3°

equation 1....... 5x-y=11°

equation 2......4x-y=3°

using elimination method x=8°

y=29°

5 0

3 years ago

Find the sum of the positive integers less than 200 which are not multiples of 4 and 7

taurus [48]

Answer:

$12942$ is the sum of positive integers between $1$ (inclusive) and $199$ (inclusive) that are not multiples of $4$ and not multiples $7$ .

Step-by-step explanation:

For an arithmetic series with:

$a_1$ as the first term,
$a_n$ as the last term, and
$d$ as the common difference,

there would be $\displaystyle \left(\frac{a_n - a_1}{d} + 1\right)$ terms, where as the sum would be $\displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n)$ .

Positive integers between $1$ (inclusive) and $199$ (inclusive) include:

$1,\, 2,\, \dots,\, 199$ .

The common difference of this arithmetic series is $1$ . There would be $(199 - 1) + 1 = 199$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}$ .

Similarly, positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $4$ include:

$4,\, 8,\, \dots,\, 196$ .

The common difference of this arithmetic series is $4$ . There would be $(196 - 4) / 4 + 1 = 49$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}$

Positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $7$ include:

$7,\, 14,\, \dots,\, 196$ .

The common difference of this arithmetic series is $7$ . There would be $(196 - 7) / 7 + 1 = 28$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}$

Positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $28$ (integers that are both multiples of $4$ and multiples of $7$ ) include:

$28,\, 56,\, \dots,\, 196$ .

The common difference of this arithmetic series is $28$ . There would be $(196 - 28) / 28 + 1 = 7$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}$ .

The requested sum will be equal to:

the sum of all integers from $1$ to $199$ ,
minus the sum of all integer multiples of $4$ between $1\!$ and $199\!$ , and the sum integer multiples of $7$ between $1$ and $199$ ,
plus the sum of all integer multiples of $28$ between $1$ and $199$ - these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

$19900 - 4900 - 2842 + 784 = 12942$ .

8 0

3 years ago

What is the check digits (d) for the master card number 5130 7201 2608 209d <br> A)1 B)3 C)5 D)7

LenKa [72]

I hope this is just a maths problem coz if this is your card number I wouldn't be putting it on here for all to see.

6 0

3 years ago

I want to know the answers to the ones circled

LenaWriter [7]

Hello! I will do my best to help you understand and receive the answers.

Let's begin with our first question..

15.) Dao has 2 3/8 pounds of hamburger meat. He is making 1/4 pound burgers. How many burgers can he make?

For this problem we will have to use division. Our equation (use a calculator if needed) is 2 3/8 divided by 1/4 which equals 3.

Your final answer should be : Dao can make 3 hamburgers total.

I would answer the next question, but I believe from this information above you can try and figure it out. If you are still stuck, message me and i can help you from there.

:))

4 0

3 years ago