Answer:
(2, 1).
Step-by-step explanation:
x^2 - 4x + 5 = 0
(x - 2)^2 - 4 + 5 = 0
(x - 2)^2 + 1 = 0
The vertex is at (2, 1).
Answer:
The function that represents the mass of the sample after t days is 
.
The percentage rate of change per hour is of -2.46%.
Step-by-step explanation:
Exponential amount of decay:
The exponential amount of decay for an amount of a substance after t days is given by:
In which A(0) is the initial amount, and r is the decay rate, as a decimal.
Element X is a radioactive isotope such that its mass decreases by 59% every day. The experiments starts out with 390 grams of Element X.
This means, respectively, that 
So
The function that represents the mass of the sample after t days is .
Hourly rate of change:
Decreases by 59% every day, which means that for 24 hours, the rate of change is of -59%. So
-59%/24 = -2.46%
The percentage rate of change per hour is of -2.46%.
Answer: hello your question lacks some data hence I will be making an assumption to help resolve the problem within the scope of the question
answer:
≈ 95 units ( output level )
Step-by-step explanation:
Given data :
P = 2000 - Q/10
TC = 2Q^2 + 10Q + 200 ( assumed value )
<u>The output level where a purely monopolistic market will maximize profit</u>
<u>at MR = MC </u>
P = 2000 - Q/10 ------ ( 1 )
PQ = 2000Q - Q^2 / 10 ( aka TR )
MR = d (TR ) / dQ = 2000 - 2Q/10 = 2000 - Q/5
TC = 2Q^2 + 10Q + 200 ---- ( 2 )
MC = d (TC) / dQ = 4Q + 10
equating MR = MC
2000 - Q/5 = 4Q + 10
2000 - 10 = 4Q + Q/5
1990 = 20Q + Q
∴ Q = 1990 / 21 = 94.76 ≈ 95 units ( output level )
=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2
step by step
(2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x(x+4)
=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x+4)
=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x)+((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(4)
=−640x10+3840x9+4544x8−58904x7+91128x6−40608x5+128x4+512x3−2560x9+15360x8+18176x7−235616x6+364512x5−162432x4+512x3+2048x2
=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2
2: Midpoint of segment AC is given as B3: Given4: Knowing that AC~=BC, AC~= DE
