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jonny [76]
3 years ago
6

A circle has a radius of 11 inches and a central angle AOB that measures 45°. What is the area of sector AOB? Use 3.14 for pi an

d round your answer to the nearest tenth.
a. 47.5 in2
b. 11.9 in2
c. 8.6 in2
d. 4.3 in2
Mathematics
2 answers:
Vesna [10]3 years ago
7 0
The answer is A from what my teacher taught me
Lerok [7]3 years ago
5 0

Answer:

47.461632987542

Step-by-step explanation:

My teacher told me it was this answer, don't know how.

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ehidna [41]

Answer:

no

Step-by-step explanation:

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2 years ago
A rocking horse has a weight limit of 60 pounds.
Naddika [18.5K]
33 divided by 60= 0.55
0.55 x 100= 55

The answer is 55%
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2 years ago
A spring has a natural length of 7 m. If a 4-N force is required to keep it stretched to a length of 11 m, how much work W is re
bezimeni [28]

Answer:

18 J is the work required to stretch a spring from 7 m to 13 m.

Step-by-step explanation:

The work done is defined to be the product of the force F and the distance d  that the object moves:

W=Fd

If F is measured in newtons and d<em> </em>in meters, then the unit for is a newton-meter, which is called a joule (J).

This definition work as long as the force is constant, but if the force is variable like in this case, we have that the work done is given by

W=\int\limits^b_a {f(x)} \, dx

Hooke’s Law states that the force required to maintain a spring stretched x    units beyond its natural length is proportional to

f(x)=kx

where k is a positive constant (called the spring constant).

To find how much work W is required to stretch it from 7 m to 13 m you must:

Step 1: Find the spring constant

We know that the spring has a natural length of 7 m and a 4 N force is required to keep it stretched to a length of 11 m. So, applying Hooke’s Law

4=k(11-7)\\\\\frac{k\left(11-7\right)}{4}=\frac{4}{4}\\\\k=1

Thus F=x

Step 2: Find the the work done in stretching the spring from 7 m to 13 m.

Recall that the natural length is 7 m, so when we stretch the spring from 7 m to 13 m, we are stretching it by 6 m beyond its natural length.

Work needed to stretch it by 6 m beyond its natural length

W=\int\limits^6_0 {x} \, dx \\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1\\\\\left[\frac{x^{1+1}}{1+1}\right]^6_0\\\\\left[\frac{x^2}{2}\right]^6_0=18

18 J is the work required to stretch a spring from 7 m to 13 m.

5 0
2 years ago
What is the measure of WUT?
Arada [10]

Answer:

38°

Step-by-step explanation:

4x-6x = -6 - 10

-2x = -16

__ __

-2 -2

x = 8

(6x-10)

(6(8)-10)

48-10

38°

6 0
3 years ago
LIKE I ACTUALLY NEED HELP THIS IS LITERAL TESTING NOT NO QUIZ.
Mekhanik [1.2K]

Answer:

2 because if x=0 y=1 and 2 is closest so a and b

4 0
2 years ago
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