Find the fifth term of a sequence whose first term is 8 and common ratio is 3/2
1 answer:
Answer:
Option c. 81/2
Step-by-step explanation:
Fifth term: a5=?
First term: a1=8
Common ratio: r=3/2
an=a1*r^(n-1)
with n=5
a5=a1*r^(5-1)
a5=a1*r^4
Replacing the known values:
a5=8*(3/2)^4
a5=8*(3)^4/(2)^4
a5=8*81/16
Simplifying: Dividing the numerator and denominator by 8:
a5=(8*81/8)/(16/8)
a5=81/2
Answer: Option c. 81/2
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-1/2 = -3/6
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hope this helps
Answer:
Step-by-step explanation:
3(10+n) = 25
30 +3n =25
30-30 and 25-30=
3n=-5
3/3 and 5/-3
20% * 300 = 2 * (10% * 300) = 2*30 = 60
Answer:
I think -1 cuz 2+1--1 so yh I guess
