Question

Find the fifth term of a sequence whose first term is 8 and common ratio is 3/2

Answer 1

Answer:

Option c. 81/2

Step-by-step explanation:

Fifth term: a5=?

First term: a1=8

Common ratio: r=3/2

an=a1*r^(n-1)

with n=5

a5=a1*r^(5-1)

a5=a1*r^4

Replacing the known values:

a5=8*(3/2)^4

a5=8*(3)^4/(2)^4

a5=8*81/16

Simplifying: Dividing the numerator and denominator by 8:

a5=(8*81/8)/(16/8)

a5=81/2

Answer: Option c. 81/2