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storchak [24]
3 years ago
14

NEED HELP ASAP ALGEBRA 1

Mathematics
2 answers:
oee [108]3 years ago
8 0

Answer: the answer is J

Step-by-step explanation:

Akimi4 [234]3 years ago
3 0

Answer:

The answer is the last one.

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A principal of a school with 484 students collected information about how many of the students wear glasses
Nana76 [90]

Answer:

students

Step-by-step explanation:

you're missing a part?

6 0
3 years ago
PLEASE HELP IN COMPLETE SENTENCES I WILL MARK BRAINLIEST
SVEN [57.7K]

Answer:

8km / 9 hours

Step-by-step explanation:

see the point is on

x axis = 9 = 9 hours

y axis = 8 = 8 kilometers

so the average speed of bus is 8 km in 9 hours

4 0
3 years ago
Read 2 more answers
Which polynomial is represented by the algebra tiles?
kogti [31]

A. 2x2 – 4x – 6

Looking at the diagram, there two positive x's to the power of 2, and there are four negative x and six minus signs. Inspecting it and adding all the same terms, you will get the quadratic expression 2x^2 - 4x - 6.

8 0
3 years ago
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The Quik-Clean Car Wash charges $15 for a car wash plus $2.50 per gallon for unleaded gasoline. The Mighty Clean Car Wash charge
DerKrebs [107]

Answer:

<em>Josh would need to purchase 20 gallons of gas for the cost to be the same at each car wash</em>

Step-by-step explanation:

We need to model both car wash's costs. The Quik-Clean Car Wash charges $15 for a car wash plus $2.50 per gallon for unleaded gasoline. If x is the number of gallons of unleaded gasoline. the total charges of this store are:

C1=15+2.5*x

The Mighty Clean Car Wash charges $10 for a carwash plus $2.75 per gallon for unleaded gasoline. Following the same procedure, their costs are:

C2=10+2.75*x

Josh wants to know how many gallons of gas will make both businesses charge the same. Equating both equations:

15+2.5*x=10+2.75*x

Simplifying:

-0.25x=-5

Solving:

x=-5/(-0.25)=20

Josh would need to purchase 20 gallons of gas for the cost to be the same at each car wash

3 0
4 years ago
Find the volume of the solid generated by revolving the area bounded by y=x^2 and x-axis from [0,2] around the x-axis
lesya [120]

Answer:  \dfrac{32\pi }{5}\ \text{unit}^3

Step-by-step explanation:

Given

The area is bounded by y=x^2 and x-axis from [0,2]

The volume generated for y=f(x) when rotated about the x-axis in the interval [a,b] is

V=\int_a^b\pi y^2dx

Insert the values

\Rightarrow V=\int_0^2\pi x^4dx\\\\\Rightarrow V=\pi \int_0^2x^4dx\\\\\Rightarrow V=\pi \left[ \dfrac{x^5}{5}\right]_0^2\\\\\Rightarrow V=\dfrac{2^5\pi }{5}\\\\\Rightarrow V=\dfrac{32\pi }{5}\ \text{unit}^3

8 0
3 years ago
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