They both drive 18 miles north, so if amir goes 18 miles west and Anna goes East, it is just 32 minus 18: she drove 12 miles east.
Answer:
36:39
= 36/39 (divide by 3)
= 12/13
= <u>12:13 (option C)</u>
2 ways: Easy and hard
Hard=A
Easy=B
A: 1/2x+4
work from there so we do fun stuff with it
make something that can be simplified so
1/2x+4 times (2/2)=x+8
now square the whole thing and put the result in a square root thingie
(x+8)^2=x^2+16x+64

multiply the whole thing by 4/4 and put
![\sqrt{16} [\tex] on top so then [tex] \sqrt{x^2+16x+64}](https://tex.z-dn.net/?f=%20%5Csqrt%7B16%7D%20%5B%5Ctex%5D%20on%20top%20so%20then%20%0A%5Btex%5D%20%5Csqrt%7Bx%5E2%2B16x%2B64%7D%20)
times

=

=

to solve it, factor out the 16 in the square root and then square root 16 to get 4
then it will be (4 times square root of equation)/4=square root of equatio
factor square root of equation and square root it and get x+8
divide by 2 to get 1/2x+4
B: 1/2x+4
put stuff that cancels out
1/2x+3x-3x+4+56-56
move them around
3 and 1/2x-3x+60-56
or
2x-3x+1 and 1/2x+30-20+30-36
then just add like terms to solve
The unknown angles in the cyclic quadrilateral is as follows:
∠BGX = 74° (sum of angles in a triangle)
∠BGF = 180° (opposite angles of cyclic quadrilateral are supplementary)
∠BCF = 100°(sum of angles in a triangle)
∠BCG = 26°
∠BFG = 22°
<h3>Cyclic Quadrilateral</h3>
A cyclic quadrilateral has all its angles equal to 360 degrees. The sum of angles in a cyclic quadrilateral is equals to 360 degrees.
Let's find the missing angles as follows:
∠BGX = 180 - 48 - 58 = 74° (sum of angles in a triangle)
∠BGF = 180 - 100 = 80° (opposite angles of cyclic quadrilateral are supplementary)
∠BCF = 180 - 22 - 58 = 100°(sum of angles in a triangle)
∠BCG = 100 - 74 = 26°
∠BFG ≅ CBF = 22°(alternate angles)
learn more on angles here: brainly.com/question/19430381