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bekas [8.4K]
3 years ago
5

Sketch the general shape of each function. Then state the end behavior of the function.

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0
Both the general shape of a polynomial and its end behavior are heavily influenced by the term with the largest exponent. The most complex behavior will be near the origin, as all terms impact this behavior, but as the graph extends farther into positive and/or negative infinity, the behavior is almost totally defined by the first term. When sketching the general shape of a function, the most accurate method (if you cannot use a calculator) is to solve for some representative points (find y at x= 0, 1, 2, 5, 10, 20). If you connect the points with a smooth curve, you can make projections about where the graph is headed at either end.
 End behavior is given by:
1. x^4. Terms with even exponents have endpoints at positive y ∞ for positive and negative x infinity. 
2. -2x^2. The negative sign simply reflects x^2 over the x-axis, so the end behavior extends to negative y ∞ for positive and negative x ∞. The scalar, 2, does not impact this.
3. -x^5. Terms with odd exponents have endpoints in opposite directions, i.e. positive y ∞ for positive x ∞ and negative y ∞ for negative x ∞. Because of the negative sign, this specific graph is flipped over the x-axis and results in flipped directions for endpoints.
4. -x^2. Again, this would originally have both endpoints at positive y ∞ for positive and negative x ∞, but because of the negative sign, it is flipped to point towards negative y ∞.
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Subproblem 1

Set the factor '(4 + x2)' equal to zero and attempt to solve:
 Simplifying 4 + x2 = 0 Solving 4 + x2 = 0
 Move all terms containing x to the left, all other terms to the right.
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The solution to this equation could not be determined.
 This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve:
 Simplifying 2 + x = 0 Solving 2 + x = 0
 Move all terms containing x to the left, all other terms to the right.
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Sub-problem 3

Set the factor '(-2 + x)' equal to zero and attempt to solve:
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 Move all terms containing x to the left, all other terms to the right.
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